当我从 xib 控制拖动导出时，默认情况下我得到了 unsafe_unretained 属性。我正在使用 Xcode 9.1。以下代码是它的样子。
@property (unsafe_unretained, nonatomic) IBOutlet UILabel *shIndexLabel;
最佳答案
__unsafe_unretained specifies a reference that does not keep the referenced object alive and is not set to nil when there are no strong references to the object. If the object it references is deallocated, the pointer is left dangling.
以上摘自 Apple 文档。所以回答你的问题为什么 ?
It is not possible for the Swift compiler to know if these references are really intended to be strong (+1) or unretained (+0)
此更改涉及到 swift 编译器。他们制作了 __unsafe_unretained 默认情况下。
关于ios - 为什么 Xcode 9 默认更改我的 socket unsafe_unretained，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/47344664/