ios - 使用快速语言在NSMutableURLRequest URL中引起日期字符串错误

Question

转换为String后我正在传递日期，但导致错误

unexpectedly found nil while unwrapping a value

这是请求的代码

let url = SERVICE_URL + "GetHistoryDataByTerminalNo?TerminalNo=\(VehicleList.SelectedTerminal.selectedTerminalId)&fromDate=\(fromDateText)&toDate=\(endDateText)"
    
let request = NSMutableURLRequest(url: NSURL(string: url)! as URL,
                          cachePolicy: .useProtocolCachePolicy,
                       timeoutInterval: 30.0)
request.httpMethod = "GET"
request.allHTTPHeaderFields = headers

更新
我得到这个网址
http://labs2.unitedtracker.com/api/Trackers/GetHistoryDataByTerminalNo?TerminalNo=351535058776063&fromDate=2020-08-23 14:15:52.000＆toDate = 2020-08-23 16:15:52.000

Answer 1

您不能只将带有空格的字符串放入URL中，而必须先对其进行URL编码。
首先，添加extension进行URL编码:

extension String {
    public var urlEncoded: String {
        var allowedCharacters = CharacterSet.urlQueryAllowed
        allowedCharacters.remove(charactersIn: "!*'();:@&=+$,/?%#[]")

        return addingPercentEncoding(withAllowedCharacters: allowedCharacters) ?? ""
    }
}

其次，对参数值进行编码:

let url = SERVICE_URL + "GetHistoryDataByTerminalNo?TerminalNo=\(VehicleList.SelectedTerminal.selectedTerminalId.urlEncoded)&fromDate=\(fromDateText.urlEncoded)&toDate=\(endDateText.urlEncoded)"

或者，您可以使用URLComponents和URLQueryItem生成您的URL。