我需要从sqlite数据库动态获取表格名称。
我的代码
-(void) readItemsFromDatabaseforTable:(NSString *)tableName {
// Setup the database object
sqlite3 *database;
// Init the animals Array
itemsList = [[NSMutableArray alloc] init];
// Open the database from the users filessytem
if(sqlite3_open([databasePath UTF8String], &database) == SQLITE_OK) {
// Setup the SQL Statement and compile it for faster access
const char *sqlStatement = "select * from %@",tableName ;
sqlite3_stmt *compiledStatement;
if(sqlite3_prepare_v2(database, sqlStatement, -1, &compiledStatement, NULL) == SQLITE_OK) {
// Loop through the results and add them to the feeds array
while(sqlite3_step(compiledStatement) == SQLITE_ROW) {
// Read the data from the result row
NSString *aName = [NSString stringWithUTF8String:(char *)sqlite3_column_text(compiledStatement, 1)];
NSInteger aDescription =(compiledStatement, 2);
// NSString *aImageUrl = [NSString stringWithUTF8String:(char *)sqlite3_column_text(compiledStatement, 3)];
// Create a new animal object with the data from the database
Category *item = [[Category alloc] initWithName:aName Quantity:aDescription];
// Add the animal object to the animals Array
[itemsList addObject:item];
[item release];
}
}
// Release the compiled statement from memory
sqlite3_finalize(compiledStatement);
}
sqlite3_close(database);
}
但是我没有得到。
我收到一条警告，未使用变量 tableName。
实际字符串是 const char *sqlStatement = "select * from allcategories";
我如何在该类别中动态传递该表名称。
谁能帮帮我吗？
提前谢谢你。
最佳答案
试试这个，
NSString *sql_str = [NSString stringWithFormat:@"select * from %@", tableName];
const char *sqlStatement = (char *)[sql_str UTF8String];
关于iphone - 如何在sqlite查询中传递表名，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/5337954/