我创建一个自定义AQGridViewCell,如下所示:
- (AQGridViewCell *) gridView: (AQGridView *) aGridView cellForItemAtIndex: (NSUInteger) index
{
static NSString * PlainCellIdentifier = @"PlainCellIdentifier";
GridViewCell * cell = (GridViewCell *)[aGridView dequeueReusableCellWithIdentifier:@"PlainCellIdentifier"];
if ( cell == nil )
{
cell = [[GridViewCell alloc] initWithFrame: CGRectMake(3.333, 3.3336, 100, 100)
reuseIdentifier: PlainCellIdentifier];
}
NSString *stringURL = [[featuredStories objectAtIndex:index] objectAtIndex:1];
NSLog(@"stringURL: %@", stringURL);
NSURL *url = [NSURL URLWithString:stringURL];
[cell.imageView setImageWithURL:url placeholderImage:[UIImage imageNamed:@"example0.png"]];
cell.storyID = [[featuredStories objectAtIndex:index] objectAtIndex:0];
return cell;
}
当您选择像这样的单元格时,我已经添加了该方法:
- (void) gridView:(AQGridView *)gridView didSelectItemAtIndex:(NSUInteger)index {
//I want to NSLog the cell.storyID here
NSLog (@"Selected theArgument=%d\n", index);
}
如何在
storyID
中访问cell
中的gridView:(AQGridView *)gridView didSelectItemAtIndex:(NSUInteger)index
?
最佳答案
将您的didSelectItemAtIndex
更新为以下内容
- (void) gridView:(AQGridView *)gridView didSelectItemAtIndex:(NSUInteger)index {
//Get the cell at the selected index
GridViewCell * cell = (GridViewCell *)[grid cellForItemAtIndex:index];
NSLog(@"Story Id = %@", cell.storyID);
}
关于ios - AQGridView选择单元格,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/11024353/