ios - 在 iOS 中解析 JSON 并将结果存储到 Array

Question

我在 iOS 中初出茅庐，所以请回答这个幼稚的问题。所以我正在尝试使用.net web 服务。我能够从网络服务获取响应，响应就像下面

<?xml version="1.0" encoding="utf-8"?><soap:Envelope     
xmlns:soap="http://schemas.xmlsoap.org/soap/envelope/"    
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" 
xmlns:xsd="http://www.w3.org/2001/XMLSchema"><soap:Body><getDoctorListResponse 
xmlns="http://tempuri.org/"><getDoctorListResult>
[
  {

    "Zone": "CENTRAL NORTH",
    "DoctorName": "Dr Ang Kiam Hwee",

  },
  {

    "Zone": "CENTRAL",
    "DoctorName": "Dr Lee Eng Seng",

  }
]
</getDoctorListResult>
</getDoctorListResponse>
</soap:Body>
</soap:Envelope>

使用下面的代码，我可以获得唯一的 json

 - (void)parser:(NSXMLParser *)parser foundCharacters:(NSString *)string
     {
            if ([currentElement isEqualToString:@"getDoctorListResult"]) {

             NSDictionary *dc = (NSDictionary *) string;
             NSLog(@"Dictionary is = \n%@", dc);

             } 
     } 

变量 dc看起来像 json等于

[
   {

    "Zone": "CENTRAL NORTH",
    "DoctorName": "Dr Ang Kiam Hwee",

  },
  {

    "Zone": "CENTRAL",
    "DoctorName": "Dr Lee Eng Seng",

  }
]

我检查了许多类似的问题，例如 Xcode how to parse Json Objects , json parsing+iphone和其他类似的问题，但无法解决我的问题。
如何获得 Zone 的值和 DoctorName并将其存储在 Array 中，然后在 TableView 中显示？

Answer 1

您需要收集<getDoctorListResult>的内容元素到实例变量中，因此将以下内容添加为私有(private)类扩展

@interface YourClass ()
{
    NSMutableString *_doctorListResultContent;
}

然后使用 XML 解析器委托(delegate)收集元素内容:

- (void) parser:(NSXMLParser *)parser
didStartElement:(NSString *)elementName
   namespaceURI:(NSString *)namespaceURI
  qualifiedName:(NSString *)qualifiedName
     attributes:(NSDictionary *)attributeDict
{
    self.currentElement = elementName;
    if ([self.currentElement isEqualToString:@"getDoctorListResult"]) {
        _doctorListResultContent = [NSMutableString new];
    }
}

- (void) parser:(NSXMLParser *)parser
foundCharacters:(NSString *)string
{
    if ([self.currentElement isEqualToString:@"getDoctorListResult"]) {
        [_doctorListResultContent appendString:string];  
    }
}

最后在 did 结束元素委托(delegate)方法中解析 JSON:

- (void)parser:(NSXMLParser *)parser
 didEndElement:(NSString *)elementName
  namespaceURI:(NSString *)namespaceURI
 qualifiedName:(NSString *)qName
{
    if ([elementName isEqualToString:@"getDoctorListResult"]) {
        NSError *error = nil;
        NSData *jsonData = [_doctorListResultContent dataUsingEncoding:NSUTF8StringEncoding];
        id parsedJSON = [NSJSONSerialization JSONObjectWithData:jsonData
                                                        options:0
                                                          error:&error];
        if (parsedJSON) {
            NSAssert([parsedJSON isKindOfClass:[NSArray class]], @"Expected a JSON array");
            NSArray *array = (NSArray *)parsedJSON;
            for (NSDictionary *dict in array) {
                NSString *zone = dict[@"Zone"];
                NSString *doctorName = dict[@"DoctorName"];

                // Store in array and then reload tableview (exercise to the reader)
            }
        } else {
            NSLog(@"Failed to parse JSON: %@", [error localizedDescription]);
        }

    }
}