我有一个包含70个对象的NSMutableArray
,它们是NSMutableDictionary
,在每个字典中我都有2个值:“distance”和“indexPath”。我想从小距离到大距离对NSMutableArray
进行排序。距离以KM为单位,使用我在此处粘贴的代码后,数组如下所示:
NSSortDescriptor *descriptor = [NSSortDescriptor sortDescriptorWithKey:@"distance" ascending:YES];
[branchDistance sortedArrayUsingDescriptors:[NSArray arrayWithObjects:descriptor,nil]];
这是此方法的结果:
(lldb) po [branchDistance objectAtIndex:0]
(id) $1 = 0x0d6ac240 {
"<NSIndexPath 0xd6cf180> 1 indexes [0]" = indexPath;
"8.078547" = distance;
}
(lldb) po [branchDistance objectAtIndex:1]
(id) $2 = 0x0d6a64a0 {
"<NSIndexPath 0xd6cf3b0> 1 indexes [1]" = indexPath;
"45.044069" = distance;
}
(lldb) po [bran(lldb) po [branchDistance objectAtIndex:2]
(id) $4 = 0x0d6cf550 {
"<NSIndexPath 0xd69b3f0> 1 indexes [2]" = indexPath;
"9.992081" = distance;
}
(lldb) po [branchDistance objectAtIndex:3]
(id) $5 = 0x0d6cf750 {
"283.356727" = distance;
"<NSIndexPath 0xd6cf480> 1 indexes [3]" = indexPath;
}
我想使用
NSMutableArray
内的这个“距离”键值,将NSMutableDictionary
从小数到大数进行排序。我从网络和stackoverflow尝试了一些代码,但是找不到适合我的东西。请帮我!
谢谢!
最佳答案
我假设使用NSNumber
对象将距离值存储在字典中:
NSArray *sortedArray = [branchDistance sortedArrayUsingComparator:^(id obj1, id obj2) {
NSNumber *distance1 = [(NSDictionary *)obj1 objectForKey:@"distance"];
NSNumber *distance2 = [(NSDictionary *)obj2 objectForKey:@"distance"];
return [distance1 compare:distance2];
}];
关于objective-c - 按字典键的值对包含NSMutableDictionary的NSMutableArray进行排序,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/13286997/