ios - UITextField 中的 UIPicker

Question

当我在 UITextField 内单击时，我想显示一个选择器。这是我的代码(有效):

 [super viewDidLoad];
// Picker View dei Tipi
pickerTipo= [[UIPickerView alloc] init];
pickerTipo.showsSelectionIndicator = YES;
UIToolbar* keyboardDoneButtonView = [[UIToolbar alloc] init];

[keyboardDoneButtonView sizeToFit];
UIBarButtonItem* doneButton = [[UIBarButtonItem alloc] 
                               initWithTitle:
                               @"Fine"  style:UIBarButtonItemStyleBordered 
                               target:self 
                               action:@selector(pickerDoneClicked:)];

[keyboardDoneButtonView setItems:[NSArray arrayWithObjects:doneButton, nil]];

self.textTipo.inputAccessoryView = keyboardDoneButtonView;
[self.textTipo resignFirstResponder];
self.textTipo.inputView = pickerTipo;
self.textTipo.delegate  = self;

选择器和附件 View 正确显示。问题是 UITextField 仍然是可编辑的，也就是说我仍然可以在 UITextField 中输入。我希望当显示选择器时，在 UITextField 内不启用任何编辑。

[解决了}
按照接受的答案，正确的代码是:

- (BOOL)textField:(UITextField *)textField shouldChangeCharactersInRange:(NSRange)range   replacementString:(NSString *)string
{
 if (textField == self.textTipo || textField == self.textStato)
    return NO;
 else
     return YES;
} 

Answer 1

- (BOOL)textField:(UITextField *)textField shouldChangeCharactersInRange:(NSRange)range replacementString:(NSString *)string
{

    if([textField.restorationIdentifier isEqualToString:@"textFieldIdentifier"])
    {
        return NO;
    }
}

希望能帮助到你。