试图解析我使用我的应用程序获得的推送。
但我在这里遇到一些问题:
NSString *resourcePath = [[launchOptions objectForKey:UIApplicationLaunchOptionsRemoteNotificationKey] objectForKey:@"aps"];
NSLog(@"resourcePath: %@", resourcePath);
NSLog
{
alert = cb;
badge = 1;
sound = default;
url = cxb; }
我 NSLog 它作为字符串...如何获取 URL?
谢谢!
最佳答案
它是一个字典对象。获取 url 键的对象。像这样:
NSString *resourcePathURL = [[[launchOptions objectForKey:UIApplicationLaunchOptionsRemoteNotificationKey] objectForKey:@"aps"] objectForKey:@"url"] ;
NSLog(@"URL : %@",resourcePathURL);
关于objective-c - 解析推送通知 iOS,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/8870864/