iphone - 如何获取字典数组中特定键的值？

Question

我正在获取如下数据，我想在不循环的情况下获取names= app,app1,app2这样的数据。如何在不循环的情况下实现这一目标？

(
        {
        date = "12/12/12";
        name = app;
    },
        {
        date = "11/02/12";
        name = app1;
    },
        {
        date = "14/05/12";
        name = app2;
    }
)

Answer 1

是的。可以这样尝试。这里不需要采取任何循环的概念，这在有大量数据时非常有用。

NSString *str=[[array1 valueForKeyPath:@"name"] componentsJoinedByString:@","];
NSLog(@"desired string:%@",str);


NSMutableDictionary *dict = [[NSMutableDictionary alloc]init];
    [dict setObject:@"app" forKey:@"name"];

    NSMutableDictionary *dict1 = [[NSMutableDictionary alloc]init];
    [dict1 setObject:@"app1" forKey:@"name"];


    NSMutableDictionary *dict2 = [[NSMutableDictionary alloc]init];
    [dict2 setObject:@"app2" forKey:@"name"];
    NSArray *array1 = [[NSArray alloc]initWithObjects:dict,dict1,dict2, nil];

    NSString *str=[[array1 valueForKeyPath:@"name"] componentsJoinedByString:@","];
    NSLog(@"desired string:%@",str);

    O/P:- app,app1,app2