ios - 加速度计倾斜问题

Question

因此，这是我正在开发的第一款练习游戏，并且是首次使用加速度计，因此如果答案很明显，请提前道歉。还要提供代码和解释。

因此，在游戏的一部分中，我有一个球没有在屏幕上滚动。球根据倾斜度移动。此应用程序的设备方向仅适用于横向。当我握住手机横向并向上和向下倾斜手机时，球会相应移动。 (将顶端向下倾斜，使球向上滚动，将底端向下倾斜，使球向下滚动)。因此，这2个倾斜都很好。现在，当我将屏幕向左倾斜时，球会向右滚动，反之亦然。我想要的是屏幕向左倾斜，球向左倾斜，屏幕向右倾斜，球向右倾斜。我的以下代码如何解决此问题。我知道它就像更改两行一样简单。

//delegate method
-(void)outputAccelertionData:(CMAcceleration)acceleration
{
    currentMaxAccelX = 0;
    currentMaxAccelY = 0;


    if(fabs(acceleration.x) > fabs(currentMaxAccelX))
    {
        // this needs to be currentMaxAccelY not currentMaxAccelX for those of you thinking this is the solution
        currentMaxAccelY = acceleration.x; 
    }
    if(fabs(acceleration.y) > fabs(currentMaxAccelY))
    {
        // this needs to be currentMaxAccelX not currentMaxAccelY for those of you thinking this is the solution
        currentMaxAccelX = acceleration.y;
    }
}

-(void)update:(CFTimeInterval)currentTime {

    /* Called before each frame is rendered */


    float maxY = 480;
    float minY = 0;


    float maxX = 320;
    float minX = 0;

    float newY = 0;
    float newX = 0;

    //Im pretty sure the problem is in this if statement as this is what deals with the left and right tilt
    if(currentMaxAccelX > 0.05){
        newX = currentMaxAccelX * 10;
    }
    else if(currentMaxAccelX < -0.05){
        newX = currentMaxAccelX*10;
    }
    else{
        newX = currentMaxAccelX*10;
    }

    newY = currentMaxAccelY *10;

    newX = MIN(MAX(newX+self.ball.position.x,minY),maxY);
    newY = MIN(MAX(newY+self.ball.position.y,minX),maxX);


    self.ball.position = CGPointMake(newX, newY);

}

Answer 1

所以我解决了这个问题。问题出在我的数学上。我应该乘以负10而不是乘以10以获得相反的效果。

if(currentMaxAccelX > 0.05){
        newX = currentMaxAccelX * -10;
    }
    else if(currentMaxAccelX < -0.05){
        newX = currentMaxAccelX*-10;
    }
    else{
        newX = currentMaxAccelX*-10;
    }