我正在使用 cURL 从外部站点返回数据。如何使用 PHP 返回站点的基本 URL?
例如,我有这个 URL:
http://www.bestbuy.com/site/Insignia%26%23153%3B+-+55%22+Class+/+1080p+/+120Hz+/+LCD+HDTV/2009148.p?id=1218317000232&skuId=2009148
我只想要http://www.bestbuy.com
谢谢!
最佳答案
$url = "http://www.bestbuy.com/site/Insignia%26%23153%3B+-+55%22+Class+/+1080p+/+120Hz+/+LCD+HDTV/2009148.p?id=1218317000232&skuId=2009148"; echo ""; print_r(parse_url($url));<p></p>
//Would give you Array ( [scheme] => http [host] => www.bestbuy.com [path] => /site/Insignia%26%23153%3B+-+55%22+Class+/+1080p+/+120Hz+/+LCD+HDTV/2009148.p [query] => id=1218317000232&skuId=2009148 )
关于php - 如何获取外部网站的基本 URL,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/9426538/