ios - 基于属性与JSONModel的动态模型级联

Question

给定以下JSON blob:

[
  {
    type: "audio",
    title: "Audio example title",
  },
  {
    type: "video",
    title: "Video example title",
  },
  {
    type: "audio",
    title: "Another audio example title",
  },
]

和两个JSONModel模型类(AudioModel，VideoModel)。在将JSON映射到模型时，JSONModel是否可以基于type属性自动创建这些模型类之一？

Answer 1

可以使用for..in循环并检查type属性并根据如下类型创建Model对象

NSMutableArray *audioModelArray = [NSMutableArray alloc] init];
NSMutableArray *videoModelArray = [NSMutableArray alloc] init];

    for(NSdictionary *jsonDict in jsonArray) {
        if(jsonDict[@"type"] isEqualToString:@"audio") {
             AudioModel *audio  = [AudioModel alloc]initWithTitle:jsonDict[@"title"]]; 
            [audioModelArray addObject: audio];
        } else {
          VideoModel *audio  = [VideoModel alloc]  initWithTitle:jsonDict[@"title"]];
         [videoModelArray addObject: audio];
        }
    }

那么您可以遍历audioModelArray和videoModelArray对象以访问audoModel和videoModel对象及其属性。