ios - 通过此方法更改NSURL字符串stringByAddingPercentEncodingWithAllowedCharacters

Question

我有一个弦

https://www.example.com/abc/Gesture-abc-mobile-app_%257E0177cae9d41f573e5f?source=rss

当我使用此方法在Url中对其进行转换以加载UIWebView

 NSString *str = [[NSString stringWithFormat:@"%@", self.urlStr] stringByAddingPercentEncodingWithAllowedCharacters:NSCharacterSet.URLQueryAllowedCharacterSet];

输出为:

 https://www.example.com/jobs/Gesture-initiated-mobile-app_%257E0177cae9d41f573e5f?source=rss%0A%20%20%20%20%20%20

告诉我为什么会这样...

Answer 1

字符串末尾还有多余的字符-回车符和准确的空格:

NSString *urlStr = @"https://www.example.com/abc/Gesture-abc-mobile-app_%257E0177cae9d41f573e5f?source=rss\n     ";

结果:

https://www.example.com/abc/Gesture-abc-mobile-app_%25257E0177cae9d41f573e5f?source=rss%0A%20%20%20%20%20

最后删除垃圾，您将获得所需的结果。