ios - 一个 UITableView 嵌入了一个 UIScrollView，滑动删除是行不通的

Question

尝试了很多方法都没有解决

就我而言，我的 View 层次结构:

UIView
  UIScrollView
  LeftContainer + RightContainer
                (in RihgtContainer) ViewContainer 
                                      TableView

我试过这些:

子类化 Scrollview 和

 - (void)touchesBegan:(NSSet *)touches withEvent:(UIEvent *)event
{
    [self.nextResponder touchesBegan:touches withEvent:event];
}

- (void)touchesMoved:(NSSet *)touches withEvent:(UIEvent *)event
{
   if(!self.dragging)
    {
        [self.nextResponder touchesMoved:touches withEvent:event];
    }
}

- (void)touchesEnded:(NSSet *)touches withEvent:(UIEvent *)event
{
    [self.nextResponder touchesEnded:touches withEvent:event];

- (BOOL)gestureRecognizer:(UIGestureRecognizer *)gestureRecognizer shouldRecognizeSimultaneouslyWithGestureRecognizer:(UIGestureRecognizer *)otherGestureRecognizer


innerTableView.scrollEnabled = YES;
innerTableView.alwaysBounceVertical = NO;

Answer 1

您可以通过托盘将 ScrollView 上的 delaysTouchesBegan 设置为 true... 就像这里 https://stackoverflow.com/a/31040918/1702413

但是 .. UITableview 继承自UIScrollView

您不应在 UIScrollView 对象中嵌入 UIWebView 或 UITableView 对象 https://stackoverflow.com/a/17121582/1702413