我有一个数组,我使用 EcmaScript-6 函数成功地将其转换为字符串格式。但是,如何使用 EcmaScript-3 执行此操作?接收端点需要 ES3 函数。
原始数组:
formdata: [
1: {name: "gender", value: "F", focus: 0, type: "radio"}
2: {name: "firstname", value: "empty", focus: 0, type: "text"}
3: {name: "lastname", value: "empty", focus: 0, type: "text"}
4: {name: "birthday", value: "empty", focus: 0, type: "text"}
5: {name: "street", value: "empty", focus: 0, type: "text"}
6: {name: "streetNo", value: "empty", focus: 0, type: "text"}
]
要求的字符串格式
let formdata = gender.radio|F|0;firstName.text|empty|1;lastName.text|empty|0;street.text|empty|0;houseNumber.text|empty|0;zip.text|empty|0;city.text|empty|0;country.select-one|de|0;birthdate-day.text|empty|0;birthdate-month.text|empty|0;birthdate-year.text|empty|0;email.email|empty|0;code.text|filled_out|0
我使用 ES6 的工作解决方案:
let res = formdata.map(({name,value,focus,type}) => `${name}.${type}|${value}|${focus}`).join(';')
我对转换为 ES3 的看法:
var res = formdata.map(({name,value,focus,type}) {
("name" + "." + "type" + "|" + "value" + "focus").join(;)
}
这个解决方案显然不起作用,而且我不确定它是否是有效的 ES3 JavaScript。
谢谢!
最佳答案
您尝试使用 ES3 的问题:
- 箭头函数少了箭头,但也是对语法的 ES6 补充
.join(;)
不是有效的 JavaScript。.join(";")
是。- ES6 中引入了解构语法
.map
是在 ES5 中引入的- 你还需要一个“|”
所以:
var formdata = [{name: "gender", value: "F", focus: 0, type: "radio"},{name: "firstname", value: "empty", focus: 0, type: "text"},{name: "lastname", value: "empty", focus: 0, type: "text"}, {name: "birthday", value: "empty", focus: 0, type: "text"},{name: "street", value: "empty", focus: 0, type: "text"},{name: "streetNo", value: "empty", focus: 0, type: "text"},];
var arr = [];
for (var i = 0; i < formdata.length; i++) {
var elem = formdata[i];
arr.push(elem.name + "." + elem.type + "|" + elem.value + "|" + elem.focus);
}
var str = arr.join(";");
console.log(str);
关于javascript - 将 JavaScript ES6 函数转换为 ES3,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/55508261/