我有一个带有状态列的表。我想要一个 Oracle sql 查询,它将仅在一行中列出每个状态中的行数。
例如,如果我的 table 是
Table A
Id Status Fkey
1 20 500
2 20 500
3 30 501
4 40 501
5 30 502
输出应该是
Fkey Count_status20 Count_status30 Count_status40
500 2 0 0
501 0 1 1
这里稍微有点扭曲
Table B
FKey TKey
500 1001
501 1001
502 1002
现在输出应该是
TKey Count_status20 Count_status30 Count_status40
1001 2 1 1
1002 0 1 0
最佳答案
如果您使用的是 Oracle 11g,那么您可以使用 PIVOT
功能:
select *
from
(
select tkey, status,
status as col
from tableB b
left join tableA a
on a.fkey = b.fkey
) src
pivot
(
count(status)
for col in ('20' as Count_Status20,
'30' as Count_Status30,
'40' as Count_Status40)
) piv;
见 SQL Fiddle with Demo
如果您没有使用 Oracle11g,那么您可以使用带有
CASE
的聚合函数陈述:select tkey,
count(case when status = 20 then 1 else null end) as Count_Status20,
count(case when status = 30 then 1 else null end) as Count_Status30,
count(case when status = 40 then 1 else null end) as Count_Status40
from tableB b
left join tableA a
on b.fkey = a.fkey
group by tkey
见 SQL Fiddle with Demo
关于Oracle sql 计算单列中不同值的实例,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/13238142/