运行命令时 cordova run ios --device
,我收到以下错误:
FIXME: Implement XCBuild support for macros in overriding parameters with condition sets:
CODE_SIGN_IDENTITY[sdk=iphoneos*] = iPhone Developer
Error: Error code 1 for command: xcodebuild with args: -xcconfig,/Users/myUser/Documents/demo-app/App/platforms/ios/cordova/build-debug.xcconfig,-workspace,HelloCordova.xcworkspace,-scheme,HelloCordova,-configuration,Debug,-destination,generic/platform=iOS,-archivePath,HelloCordova.xcarchive,archive,CONFIGURATION_BUILD_DIR=/Users/myUser/Documents/demo-app/App/platforms/ios/build/device,SHARED_PRECOMPS_DIR=/Users/myUser/Documents/demo-app/App/platforms/ios/build/sharedpch
我可以谷歌最接近的建议要么删除,然后再次添加平台,如下所示:
cordova platform remove ios
cordova platform add ios
... 或更改
build-release.xcconfig
文件引用来自 iPhone Distribution
至 iPhone Developer
对于“CODE_SIGN_IDENTITY”和“CODE_SIGN_IDENTITY[sdk=iphoneos*]”值。我已经尝试了两者,但最终还是出现了同样的错误。
我正在运行以下内容:
此外,我使用
cordova run --list
验证了该设备是否已连接。 .该设备是运行 iOS 13.3.1 的 iPhone 11 Pro。谢谢,提前感谢任何对此有所了解的人。
最佳答案
Xcode -> File -> Workspace Settings -> 并更改build设置(从下拉列表中选择旧build设置):
关于ios - 错误 - FIXME : Implement XCBuild support for macros in overriding parameters with condition sets,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/60536101/