unit-testing - Play 2 个框架单元测试 - java.lang.RuntimeException : DataSource user is null?

Question

我尝试在 MySQL 兼容模式下使用 H2 数据库在 Play 2 应用程序中运行单元测试。我在 @Before 中配置如下:

@Before
public void startApp() throws Exception {
    Map<String, String> settings = new HashMap<String, String>();
    settings.put("db.default.driver", "org.h2.Driver");
    settings.put("db.default.user", "sa");
    settings.put("db.default.password", "");
    settings.put("db.default.url", "jdbc:h2:mem:play-test-351881363;MODE=MySQL"); // TODO: use config for url
    settings.put("db.default.jndiName", "DefaultDS");
    app = Helpers.fakeApplication(settings);
    Helpers.start(app);

    databaseTester = new JndiDatabaseTester("DefaultDS");

    IDataSet expectedDataSet = new FlatXmlDataSetBuilder().build(play.Play.application()
            .resourceAsStream("/resources/dataset.xml"));
    databaseTester.setDataSet(expectedDataSet);
    databaseTester.onSetup();
}

@After
public void stopApp() throws Exception {
    databaseTester.onTearDown();
    Helpers.stop(app);
}

但是当它尝试访问数据库时，在实际测试方法中会导致 java.lang.RuntimeException: DataSource user is null?:

[ERROR] [02/12/2013 01:19:32.085] [application-akka.actor.default-dispatcher-4] [akka://application/user/load_data_task_runner_test/load_record] DataSource user is null?
java.lang.RuntimeException: DataSource user is null?
    at com.avaje.ebeaninternal.server.lib.sql.DataSourcePool.<init>(DataSourcePool.java:184)
    at com.avaje.ebeaninternal.server.lib.sql.DataSourceManager.getDataSource(DataSourceManager.java:200)
    at com.avaje.ebeaninternal.server.lib.sql.DataSourceGlobalManager.getDataSource(DataSourceGlobalManager.java:46)
    at com.avaje.ebeaninternal.server.core.DefaultServerFactory.getDataSourceFromConfig(DefaultServerFactory.java:432)
    at com.avaje.ebeaninternal.server.core.DefaultServerFactory.setDataSource(DefaultServerFactory.java:393)
    at com.avaje.ebeaninternal.server.core.DefaultServerFactory.createServer(DefaultServerFactory.java:169)
    at com.avaje.ebeaninternal.server.core.DefaultServerFactory.createServer(DefaultServerFactory.java:124)
    at com.avaje.ebeaninternal.server.core.DefaultServerFactory.createServer(DefaultServerFactory.java:64)
    at com.avaje.ebean.EbeanServerFactory.create(EbeanServerFactory.java:45)
    at com.avaje.ebean.Ebean$ServerManager.getWithCreate(Ebean.java:206)
    at com.avaje.ebean.Ebean$ServerManager.get(Ebean.java:193)
    at com.avaje.ebean.Ebean$ServerManager.access$200(Ebean.java:128)
    at com.avaje.ebean.Ebean.getServer(Ebean.java:257)
    at play.db.ebean.Model$Finder.server(Model.java:240)
    at play.db.ebean.Model$Finder.byId(Model.java:261)
    at integration.LoadRecordService.onReceive(LoadRecordService.java:50)
    at akka.actor.UntypedActor$$anonfun$receive$1.applyOrElse(UntypedActor.scala:159)
    at akka.actor.ActorCell.receiveMessage(ActorCell.scala:425)
    at akka.actor.ActorCell.invoke(ActorCell.scala:386)
    at akka.dispatch.Mailbox.processMailbox(Mailbox.scala:230)
    at akka.dispatch.Mailbox.run(Mailbox.scala:212)
    at akka.dispatch.ForkJoinExecutorConfigurator$MailboxExecutionTask.exec(AbstractDispatcher.scala:502)
    at scala.concurrent.forkjoin.ForkJoinTask.doExec(ForkJoinTask.java:262)
    at scala.concurrent.forkjoin.ForkJoinPool$WorkQueue.runTask(ForkJoinPool.java:975)
    at scala.concurrent.forkjoin.ForkJoinPool.runWorker(ForkJoinPool.java:1478)
    at scala.concurrent.forkjoin.ForkJoinWorkerThread.run(ForkJoinWorkerThread.java:104)

此处使用 dbunit 进行演化和初始化在 startApp() 中工作，在 @Test 方法中抛出异常。

我做错了什么？

附言我没有使用 play.test.Helpers.running，因为它需要 Runnable 作为参数，而 runnable 中的 run() 不能抛出异常。因此，要在单元测试中捕获异常，我必须将整个 run() 包装到 try 中，捕获异常，单元测试失败并手动记录消息。它使代码膨胀很多。这是 running() 的代码:

public static synchronized void running(FakeApplication fakeApplication, final Runnable block) {
    try {
        start(fakeApplication);
        block.run();
    } finally {
        stop(fakeApplication);
    }
}

我在我的 @Before 和 @After 中做同样的事情，可能除了一些可能导致错误的线程内容。

Answer 1

问题是由于配置中的 ebean.default 键在主配置中被注释掉了:

ebean.default="models.*"

并且为 H2 设置用户名和密码是不需要的，没有它它也能工作:

settings.put("db.default.user", "sa");
settings.put("db.default.password", "");