c++ - 为什么我的 worker 在错误的线程中工作？

Question

我有一个带有两个内部对象指针的Messenger类:

    std::unique_ptr<QThread> stdin_receiver_thread_ = nullptr;
    std::unique_ptr<ReceiverWorker> stdin_receiver_ = nullptr;

在Messenger的构造函数中，我创建了这些对象并将其分配给这些智能指针，如下所示:

Messenger::Messenger(QObject *parent) : QObject(parent) {

    // create the objects
    stdin_receiver_thread_ = std::make_unique<QThread>(); 
    stdin_receiver_ = std::make_unique<ReceiverWorker>();
    //
    qDebug() << "stdin_receiver_thread_:" << stdin_receiver_thread_.get()->thread();

    // I assign the worker to this the newly created thread
    stdin_receiver_->moveToThread(stdin_receiver_thread_.get());
    //

    connect(stdin_receiver_thread_.get(), &QThread::started, stdin_receiver_.get(), &ReceiverWorker::process);
    connect(stdin_receiver_.get(), &ReceiverWorker::receivedMessage, stdin_receiver_thread_.get(), &QThread::quit);
    connect(stdin_receiver_.get(), &ReceiverWorker::receivedMessage, stdin_receiver_.get(), &QObject::deleteLater);
    connect(stdin_receiver_thread_.get(), &QThread::finished, stdin_receiver_thread_.get(), &QObject::deleteLater);

    stdin_receiver_thread_->start();
}

在我的ReceiverWorker::process()里面
我打电话

qDebug() << "Receiverworker currentThread:" << QThread::currentThread();

现在，这两个qDebug()调用将输出不同的值:

stdin_receiver_thread_: QThread(0x20a24e57ba0)
Receiverworker currentThread: QThread(0x20a2e6f58e0)

因此，就像ReceiverWorker在与我想要的线程不同的线程中工作。我究竟做错了什么？

Answer 1

它正在做应该做的事情。术语stdin_receiver_thread_.get()->thread();产生QThread，其中stdin_receiver_thread_作为QObject存在。换句话说，您的主线程或Messenger的构建位置。
如果您只是写了:

qDebug() << "stdin_receiver_thread_:" << stdin_receiver_thread_.get();

您将获得预期的输出。

std::unique_ptr<QThread>

您不应将std::unique_ptr与称为QObject的deleteLater()一起使用。不可避免地导致双重释放/堆破坏。