javascript - 获取数组中的所有元素(Javascript)

Question

我正在尝试检查一个字符串是否包含我存储在数组中的某些单词......但是我是 JS 的新手，所以我不完全知道如何检查数组中的所有元素。
这是一个示例:

const fruits = ["apple", "banana", "orange"]

我实际上是在检查是否有人在聊天中发送脏话。

if(message.content.includes(fruits)){executed code}

但是我的问题是当我检查水果时它会做任何事情，但是当我检查数组中的特定元素时，如 fruits[0] //returns apple它实际上会检查...
所以我的问题/问题是如何检查数组中所有元素的字符串，而不仅仅是苹果。

Answer 1

您对 includes 的使用情况是错的。
来自 MDN:

The includes() method determines whether an array includes a certain value among its entries, returning true or false as appropriate.

arr.includes(valueToFind[, fromIndex])

const fruits = ["apple", "banana", "orange"];
const swearWord = "orange";

// execute is available
if (fruits.includes(swearWord))
  console.log("Swear word exists.");
else 
  console.log("Swear word doesn't exist.");

要检查其他方式，如果字符串包含数组的脏话:

const fruits = ["apple", "banana", "orange"];
const swearWord = "this contains a swear word. orange is the swear word";

// execute is available
if (checkForSwearWord())
  console.log("Swear word exists.");
else
  console.log("Swear word doesn't exist.");

function checkForSwearWord() {
  for (const fruit of fruits) 
    if (swearWord.includes(fruit)) return true;
  return false;
}