所以我使用 Lexik JWT Authentication Bundle (Symfony 2.6) 并使用以下代码成功创建了用户和 token :
$userRegistration = new UserRegistration();
$userRegistration->setPassword($request->request->get('password'));
$userRegistration->setEmail($request->request->filter('email'));
$userRegistration->setName($request->request->filter('name'));
$token = $this->jwtManager->create($RegisteredUser);
return $this->responseProvider->ok((object) [
'userId' => $RegisteredUser->getId(),
'token' => $token
]);
回复 :
"data": {
"userId": 24,
"token": "eyJhbGciOiJSUzI1NiJ9.eyJyb2xlcyI6WyJST0xFX1VTRVIiXSwidXNlcm5hbWUiOiJqYWdhZHVAaHViaWktbmV0d29yay5jb20iLCJleHAiOjE1MzYxNTI0MDAsImlhdCI6MTUzNTU0NzYwMH0.B7gnfGdW1ijAIlo9xUI0DwkGaajQAQPBkRx4ChILXRNtpLdwgEl_9gvWdiidFbSXJseS8jslOfuAFUIWATmbNBoWVa3nc8SxkIrKI29xZuN6hB7R-63RH2BKsAVPsEjgTIJoqkkCrfrSum-_d3LEf36jcXqZb8M-GRKI477IwSDDwG_7YK5v0mu8N4TATXhN0tZGNYxp8Y27EI-g0Gmj9BIiobxnqVVoBWHN5J8d-UCrXRq94ifhEiQBxkG9r_eacMscB80n1VsiN2ouKH2kX-HRxRJmcgmydxvR7RcEW-P6koTxkaZJGO6mv7auSudTFlDENpwD4OD7gtn_wMUDS_OuN8WT7rZp8lwKY9f8J9fiGyq5J-8C_HmyjW-h8WhuJmTUaKhCZ-eLgDm4Vs2IQGYkHJEDFumnIZ607MAa1CW1ChAvurqvUqJ3G4TTN4wYqAHpSKz4y8SAMLjO91cedBPH6K5i9lh5htF-mW_htem7e5ornicU_djSccgHbxfXHQYTHCnqLp7-ONfl_p4nmhIEK0wcF0gkBXbIitzeTjy7C_uf_FV1sLPE5cY3PUP42DmHrG4PuXHLv_L1EjErkrpna7pChKA_TPeiZjqMcQoE70sZw8rr8KnRF2hpABdU_M2ZXOt_vF5-T8mLmKqs0LHxE089vVC3xsAh0mUr4FE"
}
当我尝试使用
jwtManager->decode
解码其他 Controller 中的当前 token 时,问题开始了方法 :$jwt = "eyJhbGciOiJSUzI1NiJ9.eyJyb2xlcyI6WyJST0xFX1VTRVIiXSwidXNlcm5hbWUiOiJqYWdhZHVAaHViaWktbmV0d29yay5jb20iLCJleHAiOjE1MzYxNTI0MDAsImlhdCI6MTUzNTU0NzYwMH0.B7gnfGdW1ijAIlo9xUI0DwkGaajQAQPBkRx4ChILXRNtpLdwgEl_9gvWdiidFbSXJseS8jslOfuAFUIWATmbNBoWVa3nc8SxkIrKI29xZuN6hB7R-63RH2BKsAVPsEjgTIJoqkkCrfrSum-_d3LEf36jcXqZb8M-GRKI477IwSDDwG_7YK5v0mu8N4TATXhN0tZGNYxp8Y27EI-g0Gmj9BIiobxnqVVoBWHN5J8d-UCrXRq94ifhEiQBxkG9r_eacMscB80n1VsiN2ouKH2kX-HRxRJmcgmydxvR7RcEW-P6koTxkaZJGO6mv7auSudTFlDENpwD4OD7gtn_wMUDS_OuN8WT7rZp8lwKY9f8J9fiGyq5J-8C_HmyjW-h8WhuJmTUaKhCZ-eLgDm4Vs2IQGYkHJEDFumnIZ607MAa1CW1ChAvurqvUqJ3G4TTN4wYqAHpSKz4y8SAMLjO91cedBPH6K5i9lh5htF-mW_htem7e5ornicU_djSccgHbxfXHQYTHCnqLp7-ONfl_p4nmhIEK0wcF0gkBXbIitzeTjy7C_uf_FV1sLPE5cY3PUP42DmHrG4PuXHLv_L1EjErkrpna7pChKA_TPeiZjqMcQoE70sZw8rr8KnRF2hpABdU_M2ZXOt_vF5-T8mLmKqs0LHxE089vVC3xsAh0mUr4FE";
$test = $this->jwtManager->decode($jwt);
但是
JWTManager::decode()
必须实现接口(interface)Symfony\Component\Security\Core\Authentication\Token\TokenInterface
并且不期望给出字符串。我的目标只是从这个 token 中获取 userId,但找不到如何解码 token 的任何信息。有谁知道如何简单地解码 token ?
最佳答案
在不使用 JWT 库的情况下手动从 token 中获取信息非常简单。
一个 JWT 字符串由 3 部分组成:
base64url 编码的 header 和有效负载,都是 JSON“对象”和签名。所有 3 个部分由 .
分隔.
因此,您只需将 token 拆分为 3 个部分,在此处使用 explode
完成,然后解码base64url编码的字符串(base64_decode
),最后解码JSON(json_decode
):
$token = "eyJhbGciOiJSUzI1NiJ9.eyJyb2xlcyI6WyJST0xFX1VTRVIiXSwidXNlcm5hbWUiOiJqYWdhZHVAaHViaWktbmV0d29yay5jb20iLCJleHAiOjE1MzYxNTI0MDAsImlhdCI6MTUzNTU0NzYwMH0.B7gnfGdW1ijAIlo9xUI0DwkGaajQAQPBkRx4ChILXRNtpLdwgEl_9gvWdiidFbSXJseS8jslOfuAFUIWATmbNBoWVa3nc8SxkIrKI29xZuN6hB7R-63RH2BKsAVPsEjgTIJoqkkCrfrSum-_d3LEf36jcXqZb8M-GRKI477IwSDDwG_7YK5v0mu8N4TATXhN0tZGNYxp8Y27EI-g0Gmj9BIiobxnqVVoBWHN5J8d-UCrXRq94ifhEiQBxkG9r_eacMscB80n1VsiN2ouKH2kX-HRxRJmcgmydxvR7RcEW-P6koTxkaZJGO6mv7auSudTFlDENpwD4OD7gtn_wMUDS_OuN8WT7rZp8lwKY9f8J9fiGyq5J-8C_HmyjW-h8WhuJmTUaKhCZ-eLgDm4Vs2IQGYkHJEDFumnIZ607MAa1CW1ChAvurqvUqJ3G4TTN4wYqAHpSKz4y8SAMLjO91cedBPH6K5i9lh5htF-mW_htem7e5ornicU_djSccgHbxfXHQYTHCnqLp7-ONfl_p4nmhIEK0wcF0gkBXbIitzeTjy7C_uf_FV1sLPE5cY3PUP42DmHrG4PuXHLv_L1EjErkrpna7pChKA_TPeiZjqMcQoE70sZw8rr8KnRF2hpABdU_M2ZXOt_vF5-T8mLmKqs0LHxE089vVC3xsAh0mUr4FE";
$tokenParts = explode(".", $token);
$tokenHeader = base64_decode($tokenParts[0]);
$tokenPayload = base64_decode($tokenParts[1]);
$jwtHeader = json_decode($tokenHeader);
$jwtPayload = json_decode($tokenPayload);
print $jwtPayload->username;
在最后一行中,您有所需的信息。
您还可以在 https://jwt.io 上检查您的 token 查看有效负载中包含哪些字段。该网站上也有关于 JWT 的很好的介绍。
关于php - 如何使用纯 token ( token 作为字符串)从 Controller $jwtManager->decode($jwt) 解析 jwt token ,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/52108465/