c++ - 压入堆栈的值不是我弹出的C++

Question

我是C++的新手，正在尝试从文本文件中读取值，并将整数仅压入堆栈。我遇到的问题是，当我执行pop()时，从堆栈中出来的值是不同的。

例如，如果我按4，则在弹出时会显示为52。

我在做什么错，我该如何解决？

IntegerStack.cpp

#include "IntegerStack.h"
#include <cstdlib>

using namespace std;

IntegerStack::IntegerStack()
{
    used = 0;
}

void IntegerStack::push(int entry)
{
    data[used] = entry;
    ++used;
}

int IntegerStack::pop()
{
    --used;
    return data[used];

}

int IntegerStack::peek() const
{
    return data[used-1];
}

IntegerStack.h

#ifndef INTEGERSTACK_H
#define INTEGERSTACK_H

#include <cstdlib>    // Provides the type size_t.

using namespace std;

class IntegerStack
{
    public:
        // MEMBER CONSTANT
        static const std::size_t CAPACITY = 100;

        // DEFAULT CONSTRUCTOR
        IntegerStack( );                       // Inline

        // MODIFICATION MEMBER FUNCTIONS
        void push ( int entry );
        int pop ( );

        // CONSTANT MEMBER FUNCTIONS
        std::size_t size ( ) const { return used; }    // Inline
        bool is_empty ( ) const { return used == 0; }  // Inline
        int peek ( ) const;

    private:
      // DATA MEMBERS
      int data[CAPACITY];
      std::size_t used;
};

#endif // INTEGERSTACK_H

main.cpp

#include <fstream>
#include <iostream>
#include "IntegerStack.h"

using namespace std;

int main()
{
    string content;
    ifstream inputFile;
    cout << "Enter input file name: ";
    cin >> content;

    IntegerStack operandStack;

    // Open file
    inputFile.open(content.c_str());

    if(inputFile)
    {
        // Place values in the stack
        while(getline(inputFile,content))
        {
            cout << "Expression: " << content << endl;
            for (int i = 0; i < content.size(); i++)
            {
                if(isdigit(content[i]))
                {
                    cout << "Adding " << content[i] << " to operandStack" << endl;
                    operandStack.push(content[i]);

                    int number = operandStack.pop();
                    cout << "The integer we just pushed: " << number << endl;
                }
                else
                {
                    // add it to operatorStack
                }
            }
        }

    }

    // Close file
    inputFile.close();

    return 0;
}

inix.dat

8 + 4 / 2 
( 7 * 4 ) - 2

输出值

Enter input file name: infix.dat
Expression: 8 + 4 / 2
Adding 8 to operandStack
The integer we just pushed: 56
Adding 4 to operandStack
The integer we just pushed: 52
Adding 2 to operandStack
The integer we just pushed: 50
Expression: ( 7 * 4 ) - 2
Adding 7 to operandStack
The integer we just pushed: 55
Adding 4 to operandStack
The integer we just pushed: 52
Adding 2 to operandStack
The integer we just pushed: 50

Process returned 0 (0x0)   execution time : 4.762 s
Press any key to continue.

Answer 1

我能够通过将operandStack.push(content[i]);更改为operandStack.push(content[i]- '0');来解决此问题