我在我的应用程序中使用 express-graphql 和 node-fetch。我正在尝试将 graphql 与我的 api 调用一起使用来获取数据。目前我在做
const QueryType = new GraphQLObjectType({
name: "Query",
fields: () => ({
acctsFromRelation: {
type: new GraphQLList(AcctType),
args: {
id: {type: GraphQLString},
status: {type: GraphQLString}
},
resolve: (root, args) => getOpIds(args)
}
})
});
AcctType如下
const AcctType = new GraphQLObjectType({
name: "acct",
fields: () => ({
id: {type: GraphQLString},
name: {type: GraphQLString},
clientType: {type: GraphQLString},
accountStatus: {type: GraphQLString,
args: {
status: {type: GraphQLString}
}},
primaryContact: {type: contactType},
billingAddress: {type: billingType}
})
});
我正在尝试做这样的事情:
{ acctsFromRelation (id: "2") {
id
name
accountStatus (status: "active")
primaryContact {
firstName
lastName
phone
email
}
billingAddress {
address1
address2
city
state
postalCode
country
}
}
}
我在哪里获取 ID 为 2 且 accountStatus 为事件的所有帐户。
GetOpIds 如下:
function getOpIds (ids) {
return fetch(API CALL THAT GIVES IDS)
.then(res => res.json())
.then(json => json.map((element) => getAccountByUrl(element.id)))
.catch(err => err)
}
getAccountByUrl 看起来像这样
function getAccountByUrl (ids) {
return fetch(URL THAT LOOKS UP 1 ID at a TIME)
.then(res => res.json())
.then(json => json)
.catch(err => err)
}
最佳答案
你可以直接从代码中尝试这个
const query = `query AcctsFromRelation($id: ID, $status: String){acctsFromRelation(id: $id, status: $status)}`;
const variables = { id: id, status: status };
return new Promise((resolve, reject) => {
request("/graphql", query, variables).then(data => {
resolve(data.acctsFromRelation);
});
});
关于javascript - Express-GraphQL 上的多个过滤器,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/40856226/