我有一个查询,用于查找从 Controller 中的变量获得的结果。
$category = $request->request->get('category');
$catContent = $em->getRepository('PublicartelAppBundle:Content')->findByCategory($category);
public function findByCategory($category)
{
$em = $this->getEntityManager();
$dql = 'SELECT c FROM Publicartel\AppBundle\Entity\Content c';
if (!is_null($category)) {
$dql .= " WHERE c.categories.name = category";
}
$query = $this->getEntityManager()
->createQuery($dql)
->setHydrationMode(\Doctrine\ORM\Query::HYDRATE_ARRAY);
if (!is_null($category)) {
$query->setParameter('category', $category);
}
return $query->getResult();
}
但是当我为查询运行操作时,出现此错误:
[Syntax Error] line 0, col 71: Error: Expected =, <, <=, <>, >, >=, !=, got '.'
SELECT c FROM Publicartel\AppBundle\Entity\Content c WHERE c.categories.name = category
$categories 是实体内容的属性。
class Content
{
private $categories;
public function __construct()
{
$this->categories = new \Doctrine\Common\Collections\ArrayCollection();
}
public function addCategories(\Publicartel\AppBundle\Entity\Category $categories)
{
$this->categories[] = $categories;
return $this;
}
public function removeCategories(\Publicartel\AppBundle\Entity\Category $categories)
{
$this->categories->removeElement($categories);
}
public function setCategories(\Publicartel\AppBundle\Entity\Category $categories = null)
{
$this->categories = $categories;
return $this;
}
public function getCategories()
{
return $this->categories;
}
}
奇怪的是,当我获取变量时,并没有出现错误。
$category = $request->query->get('category');
最佳答案
你不能这样引用子对象:
SELECT c FROM Publicartel\AppBundle\Entity\Content c WHERE c.categories.name = :category
您需要在此之前JOIN
并使用该已加入实体的别名。像这样:
SELECT c, cat FROM Publicartel\AppBundle\Entity\Content c JOIN c.categories cat WHERE cat.name = :category
现在,要么使用 LEFT JOIN
,要么只使用 JOIN
,它应该可以工作。
关于php - symfony 错误 : Expected =, <, <=, <>, >, >=, !=, 得到 '.',我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/31273457/