我的 previous question已关闭并标记为重复,但建议的 asnwer 没有回答我的问题,并且按照建议,我在问一个新问题。
让我们使用建议的 answer .
这是代码:
String strMsg = "<soap:Envelope xmlns:soap=\"http://www.w3.org/2003/05/soap-envelope\">" +
" <soap:Header>" +
" <context xmlns=\"urn:zimbra\"/>" +
" </soap:Header>" +
" <soap:Body>" +
" <soap:Fault>" +
" <soap:Code>" +
" <soap:Value>soap:Sender</soap:Value>" +
" </soap:Code>" +
" <soap:Reason>" +
" <soap:Text>no valid authtoken present</soap:Text>" +
" </soap:Reason>" +
" <soap:Detail>" +
" <Error xmlns=\"urn:zimbra\">" +
" <Code>service.AUTH_REQUIRED</Code>" +
" <Trace>qtp1027591600-6073:1588614639199:4eacbd0257a457b6</Trace>" +
" </Error>" +
" </soap:Detail>" +
" </soap:Fault>" +
" </soap:Body>" +
"</soap:Envelope>";
InputStream is = new ByteArrayInputStream(strMsg.getBytes());
XMLInputFactory xif = XMLInputFactory.newFactory();
XMLStreamReader xsr = xif.createXMLStreamReader(is);
//Envelope
xsr.nextTag();
QName name = xsr.getName();
//Header
xsr.nextTag();
name = xsr.getName();
//Context
xsr.nextTag();
name = xsr.getName();
//Context again
xsr.nextTag();
name = xsr.getName();
//Header again
xsr.nextTag();
name = xsr.getName();
//Body
xsr.nextTag();
name = xsr.getName();
//Fault
xsr.nextTag();
name = xsr.getName();
/* IM COMMENTING THE FOLLOWING CODE BECAUSE I'M INTERESTED IN THE FAULT CONTENT
* AND EVEN IF IT TRY TO GO DEEPER I CAN'T GO PASS "VALUE" NODE
*
//Code
xsr.nextTag();
name = xsr.getName();
//Value
xsr.nextTag();
name = xsr.getName();
//throws exception, no more elements for some reason
xsr.nextTag();
name = xsr.getName();
*/
Transformer transformer = TransformerFactory.newInstance().newTransformer();
StringWriter stringWriter = new StringWriter();
transformer.transform(new StAXSource(xsr), new StreamResult(stringWriter));
StringReader sr = new StringReader(stringWriter.toString());
JAXBContext jaxbContext = JAXBContext.newInstance(Fault.class);
Unmarshaller unmarshaller = jaxbContext.createUnmarshaller();
Fault fault = (Fault) unmarshaller.unmarshal(sr); //THROWS EXCEPTION
//"unexcpected element (URI:"http://www.w3.org/2003/05/soap-envelope", local:"Fault"). Expected elements are <{}Fault>
我的故障类:
@XmlRootElement(name = "Fault")
@XmlAccessorType(XmlAccessType.FIELD)
public static class Fault {
@XmlElement(name = "Code")
private String code;
@XmlElement(name = "Reason")
private String reason;
public String getCode() {
return code;
}
public void setCode(String code) {
this.code = code;
}
public String getReason() {
return reason;
}
public void setReason(String reason) {
this.reason = reason;
}
}
我怀疑它不会起作用,因为直接在“Fault”内部的元素本身没有值,它们内部有更多元素,而且所有元素都以“soap”为前缀,我的信封结构并不完全像建议答案中的那个。
但是,我仍然无法获取“故障”节点,因为抛出了异常:
意外元素(URI:“http://www.w3.org/2003/05/soap-envelope”,本地:“故障”)。预期元素为 <{}Fault>
我有兴趣获得以下值(value):
<soap:Text>no valid authtoken present</soap:Text>"
此外,这仅适用于此类错误,可能还有其他错误,而且,当答案是肯定的时,我会得到完全不同的响应。
我真正感兴趣的是,通过以下方式找到探索信封的方法:
//pseudo code
(envelope->body->fault->reason->text != null) {reasonText = envelope->body->fault->reason->text)
但是无论我能够以何种方式达到 Reason->Text 都可以,然后我可以将脚本改编为其他机构。
先感谢您。
最佳答案
我的一个 friend 不想在这里回答,找到了一个解决方案,更好的是,他用我想要的方式找到了它:
//pseudo code
(envelope->body->fault->reason->text != null) {reasonText = envelope->body->fault->reason->text)
对于偶然发现此问题的 future 中的其他任何人,这里有一个解决方案:
String strMsg = "<soap:Envelope xmlns:soap=\"http://www.w3.org/2003/05/soap-envelope\">" +
" <soap:Header>" +
" <context xmlns=\"urn:zimbra\"/>" +
" </soap:Header>" +
" <soap:Body>" +
" <soap:Fault>" +
" <soap:Code>" +
" <soap:Value>soap:Sender</soap:Value>" +
" </soap:Code>" +
" <soap:Reason>" +
" <soap:Text>no valid authtoken present</soap:Text>" +
" </soap:Reason>" +
" <soap:Detail>" +
" <Error xmlns=\"urn:zimbra\">" +
" <Code>service.AUTH_REQUIRED</Code>" +
" <Trace>qtp1027591600-6073:1588614639199:4eacbd0257a457b6</Trace>" +
" </Error>" +
" </soap:Detail>" +
" </soap:Fault>" +
" </soap:Body>" +
"</soap:Envelope>";
strMsg = strMsg.replaceAll("soap:",""); //Had to replace soap:, not fancy but it works.
is = new ByteArrayInputStream(strMsg.getBytes());
InputSource xml = new InputSource(is);
XPath xPath = XPathFactory.newInstance().newXPath();
Object exprEval = xPath.compile("/Envelope/Body/Fault/Reason/Text/text()").evaluate(xml, XPathConstants.STRING);
if ( exprEval != null ) {
System.out.println( "Fault reason text: " + exprEval );
// This prints what's expected:
// Fault reason text: no valid authtoken present
}
你去吧。
关于java - 使用 Java 从无效的 SOAP 1.1 消息中获取值(value),我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/61602403/