python pygame如何合并循环？

Question

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Answer 1

您必须添加一个应用程序循环。主应用程序循环必须:

• 通过 pygame.event.pump() 处理事件或 pygame.event.get() .
• 根据输入事件和时间(分别为帧)更新对象的游戏状态和位置
• 清除整个显示或绘制背景
• 绘制整个场景(draw pacman)
• 通过 pygame.display.update() 更新显示或 pygame.display.flip()

clock = pygame.time.Clock()
run = True
while run:
    clock.tick(60)

    # event loop
    for event in pygame.event.get():
        if event.type == pygame.QUIT:
            run = False

    # update position
    # [...] 

    # clear the display
    screen.fill(WHITE)

    # draw the scene   
    pacman(px, py, dir_x) 

    # update the display
    pygame.display.flip()

此外，您必须相对于位置(x、y)和方向(dir_x)绘制吃 bean 人。看例子:

import pygame
pygame.init()

BLACK = (0,0,0)
YELLOW = (255, 245, 59)
WHITE = (242, 242, 242)
SIZE = (500, 500)

screen = pygame.display.set_mode(SIZE)

def pacman(x, y, dir_x):
    sign_x = -1 if dir_x < 0 else 1  
    pygame.draw.circle(screen, YELLOW, (x, y), 100,)
    pygame.draw.circle(screen, BLACK, (x, y), 100, 3)
    pygame.draw.circle(screen, BLACK, (x+10*sign_x, y-50), 10,)
    pygame.draw.polygon(screen, WHITE, ((x, y),(x+250*sign_x, y+250),(x+250*sign_x, y-150)))
    pygame.draw.line(screen, BLACK, (x, y), (x+84*sign_x, y-52), 3)
    pygame.draw.line(screen, BLACK, (x, y), (x+65*sign_x, y+68), 3)     


px, py, dir_x = 250, 250, 1 

clock = pygame.time.Clock()
run = True
while run:
    clock.tick(60)

    # event loop
    for event in pygame.event.get():
        if event.type == pygame.QUIT:
            run = False

    px += dir_x
    if px > 300 or px < 200:
         dir_x *= -1

    # clear the display
    screen.fill(WHITE)

    # draw the scene   
    pacman(px, py, dir_x) 

    # update the display
    pygame.display.flip()