javascript - APEX:如何实现循环级联选择列表(多对多)

标签 javascript sql oracle plsql oracle-apex

处理多对多关系时,如何为选择列表实现循环级联逻辑?

例如,我创建了一个简单的测试应用程序,该程序可以跟踪书籍和作者。
(这比我的实际业务场景更简单,并且更清楚地显示了问题。)

主页包含:

  • 一个提交页面
  • 的按钮
  • 书籍选择列表
  • 作者的选择列表

  • 我之所以使用“提交”按钮,是因为我的实际业务场景中包含一个非常冗长的报告,需要20-60秒才能刷新-在提交页面之前,用户需要从十几个选择列表中进行选择,拉报告。

    enter image description here

    enter image description here enter image description here

    这是一个完整的脚本,其中包含我正在使用的所有测试数据:
    CREATE table "BOOK" (
        "ID"         INTEGER GENERATED ALWAYS AS IDENTITY NOT NULL ENABLE,
        "TITLE"      VARCHAR2(100) NOT NULL ENABLE,
        constraint  "BOOK_CK" check ("TITLE"<>''),
        constraint  "BOOK_PK" primary key ("ID"),
        constraint  "BOOK_UK1" unique ("TITLE")
    )
    /
    
    CREATE table "AUTHOR" (
        "ID"         INTEGER GENERATED ALWAYS AS IDENTITY NOT NULL ENABLE,
        "NAME"       VARCHAR2(100) NOT NULL ENABLE,
        constraint  "AUTHOR_CK" check ("NAME"<>''),
        constraint  "AUTHOR_PK" primary key ("ID"),
        constraint  "AUTHOR_UK1" unique ("NAME")
    )
    /
    
    INSERT INTO BOOK (TITLE) VALUES ('BOOK01');
    INSERT INTO BOOK (TITLE) VALUES ('BOOK02');
    INSERT INTO BOOK (TITLE) VALUES ('BOOK03');
    INSERT INTO BOOK (TITLE) VALUES ('BOOK04');
    INSERT INTO BOOK (TITLE) VALUES ('BOOK05');
    INSERT INTO BOOK (TITLE) VALUES ('BOOK06');
    INSERT INTO BOOK (TITLE) VALUES ('BOOK07');
    INSERT INTO BOOK (TITLE) VALUES ('BOOK08');
    INSERT INTO BOOK (TITLE) VALUES ('BOOK09');
    INSERT INTO BOOK (TITLE) VALUES ('BOOK10');
    INSERT INTO BOOK (TITLE) VALUES ('BOOK11');
    INSERT INTO BOOK (TITLE) VALUES ('BOOK12');
    INSERT INTO BOOK (TITLE) VALUES ('BOOK13');
    INSERT INTO BOOK (TITLE) VALUES ('BOOK14');
    INSERT INTO BOOK (TITLE) VALUES ('BOOK15');
    INSERT INTO BOOK (TITLE) VALUES ('BOOK16');
    INSERT INTO BOOK (TITLE) VALUES ('BOOK17');
    INSERT INTO BOOK (TITLE) VALUES ('BOOK18');
    INSERT INTO BOOK (TITLE) VALUES ('BOOK19');
    INSERT INTO BOOK (TITLE) VALUES ('BOOK20');
    
    INSERT INTO AUTHOR (NAME) VALUES ('AUTHOR01');
    INSERT INTO AUTHOR (NAME) VALUES ('AUTHOR02');
    INSERT INTO AUTHOR (NAME) VALUES ('AUTHOR03');
    INSERT INTO AUTHOR (NAME) VALUES ('AUTHOR04');
    INSERT INTO AUTHOR (NAME) VALUES ('AUTHOR05');
    INSERT INTO AUTHOR (NAME) VALUES ('AUTHOR06');
    INSERT INTO AUTHOR (NAME) VALUES ('AUTHOR07');
    INSERT INTO AUTHOR (NAME) VALUES ('AUTHOR08');
    INSERT INTO AUTHOR (NAME) VALUES ('AUTHOR09');
    INSERT INTO AUTHOR (NAME) VALUES ('AUTHOR10');
    INSERT INTO AUTHOR (NAME) VALUES ('AUTHOR11');
    INSERT INTO AUTHOR (NAME) VALUES ('AUTHOR12');
    INSERT INTO AUTHOR (NAME) VALUES ('AUTHOR13');
    INSERT INTO AUTHOR (NAME) VALUES ('AUTHOR14');
    INSERT INTO AUTHOR (NAME) VALUES ('AUTHOR15');
    INSERT INTO AUTHOR (NAME) VALUES ('AUTHOR16');
    INSERT INTO AUTHOR (NAME) VALUES ('AUTHOR17');
    INSERT INTO AUTHOR (NAME) VALUES ('AUTHOR18');
    INSERT INTO AUTHOR (NAME) VALUES ('AUTHOR19');
    INSERT INTO AUTHOR (NAME) VALUES ('AUTHOR20');
    
    CREATE table "BOOK_AUTHOR" (
        "ID"         INTEGER GENERATED ALWAYS AS IDENTITY NOT NULL ENABLE,
        "BOOK_ID"    INTEGER NOT NULL ENABLE,
        "AUTHOR_ID"  INTEGER NOT NULL ENABLE,
        constraint  "BOOK_AUTHOR_PK" primary key ("ID"),
        constraint  "BOOK_AUTHOR_UK1" unique ("BOOK_ID","AUTHOR_ID")
    )
    /
    
    ALTER TABLE BOOK_AUTHOR ADD FOREIGN KEY (BOOK_ID)
          REFERENCES BOOK (ID) ENABLE
    /
    
    ALTER TABLE BOOK_AUTHOR ADD FOREIGN KEY (AUTHOR_ID)
          REFERENCES AUTHOR (ID) ENABLE
    /
    
    CREATE OR REPLACE VIEW "VW_BOOK_AUTHOR" AS
    SELECT ba.ID,
           ba.BOOK_ID,
           b.TITLE BOOK_TITLE,
           ba.AUTHOR_ID,
           a.NAME AUTHOR_NAME
    FROM BOOK_AUTHOR ba
    LEFT JOIN BOOK b on b.ID = ba.BOOK_ID
    LEFT JOIN AUTHOR a on a.ID = ba.AUTHOR_ID
    /
    
    INSERT INTO BOOK_AUTHOR (BOOK_ID,AUTHOR_ID) SELECT b.ID, a.ID FROM BOOK b, AUTHOR a WHERE b.TITLE='BOOK01' AND a.NAME='AUTHOR01';
    INSERT INTO BOOK_AUTHOR (BOOK_ID,AUTHOR_ID) SELECT b.ID, a.ID FROM BOOK b, AUTHOR a WHERE b.TITLE='BOOK02' AND a.NAME='AUTHOR02';
    INSERT INTO BOOK_AUTHOR (BOOK_ID,AUTHOR_ID) SELECT b.ID, a.ID FROM BOOK b, AUTHOR a WHERE b.TITLE='BOOK03' AND a.NAME='AUTHOR03';
    INSERT INTO BOOK_AUTHOR (BOOK_ID,AUTHOR_ID) SELECT b.ID, a.ID FROM BOOK b, AUTHOR a WHERE b.TITLE='BOOK04' AND a.NAME='AUTHOR04';
    INSERT INTO BOOK_AUTHOR (BOOK_ID,AUTHOR_ID) SELECT b.ID, a.ID FROM BOOK b, AUTHOR a WHERE b.TITLE='BOOK05' AND a.NAME='AUTHOR05';
    INSERT INTO BOOK_AUTHOR (BOOK_ID,AUTHOR_ID) SELECT b.ID, a.ID FROM BOOK b, AUTHOR a WHERE b.TITLE='BOOK06' AND a.NAME='AUTHOR06';
    INSERT INTO BOOK_AUTHOR (BOOK_ID,AUTHOR_ID) SELECT b.ID, a.ID FROM BOOK b, AUTHOR a WHERE b.TITLE='BOOK07' AND a.NAME='AUTHOR07';
    INSERT INTO BOOK_AUTHOR (BOOK_ID,AUTHOR_ID) SELECT b.ID, a.ID FROM BOOK b, AUTHOR a WHERE b.TITLE='BOOK08' AND a.NAME='AUTHOR08';
    INSERT INTO BOOK_AUTHOR (BOOK_ID,AUTHOR_ID) SELECT b.ID, a.ID FROM BOOK b, AUTHOR a WHERE b.TITLE='BOOK09' AND a.NAME='AUTHOR09';
    INSERT INTO BOOK_AUTHOR (BOOK_ID,AUTHOR_ID) SELECT b.ID, a.ID FROM BOOK b, AUTHOR a WHERE b.TITLE='BOOK10' AND a.NAME='AUTHOR10';
    INSERT INTO BOOK_AUTHOR (BOOK_ID,AUTHOR_ID) SELECT b.ID, a.ID FROM BOOK b, AUTHOR a WHERE b.TITLE='BOOK11' AND a.NAME='AUTHOR11';
    INSERT INTO BOOK_AUTHOR (BOOK_ID,AUTHOR_ID) SELECT b.ID, a.ID FROM BOOK b, AUTHOR a WHERE b.TITLE='BOOK12' AND a.NAME='AUTHOR12';
    INSERT INTO BOOK_AUTHOR (BOOK_ID,AUTHOR_ID) SELECT b.ID, a.ID FROM BOOK b, AUTHOR a WHERE b.TITLE='BOOK13' AND a.NAME='AUTHOR13';
    INSERT INTO BOOK_AUTHOR (BOOK_ID,AUTHOR_ID) SELECT b.ID, a.ID FROM BOOK b, AUTHOR a WHERE b.TITLE='BOOK14' AND a.NAME='AUTHOR14';
    INSERT INTO BOOK_AUTHOR (BOOK_ID,AUTHOR_ID) SELECT b.ID, a.ID FROM BOOK b, AUTHOR a WHERE b.TITLE='BOOK15' AND a.NAME='AUTHOR15';
    INSERT INTO BOOK_AUTHOR (BOOK_ID,AUTHOR_ID) SELECT b.ID, a.ID FROM BOOK b, AUTHOR a WHERE b.TITLE='BOOK16' AND a.NAME='AUTHOR16';
    INSERT INTO BOOK_AUTHOR (BOOK_ID,AUTHOR_ID) SELECT b.ID, a.ID FROM BOOK b, AUTHOR a WHERE b.TITLE='BOOK17' AND a.NAME='AUTHOR17';
    INSERT INTO BOOK_AUTHOR (BOOK_ID,AUTHOR_ID) SELECT b.ID, a.ID FROM BOOK b, AUTHOR a WHERE b.TITLE='BOOK18' AND a.NAME='AUTHOR18';
    INSERT INTO BOOK_AUTHOR (BOOK_ID,AUTHOR_ID) SELECT b.ID, a.ID FROM BOOK b, AUTHOR a WHERE b.TITLE='BOOK19' AND a.NAME='AUTHOR19';
    INSERT INTO BOOK_AUTHOR (BOOK_ID,AUTHOR_ID) SELECT b.ID, a.ID FROM BOOK b, AUTHOR a WHERE b.TITLE='BOOK20' AND a.NAME='AUTHOR20';
    
    INSERT INTO BOOK_AUTHOR (BOOK_ID,AUTHOR_ID) SELECT b.ID, a.ID FROM BOOK b, AUTHOR a WHERE b.TITLE='BOOK02' AND a.NAME='AUTHOR01';
    INSERT INTO BOOK_AUTHOR (BOOK_ID,AUTHOR_ID) SELECT b.ID, a.ID FROM BOOK b, AUTHOR a WHERE b.TITLE='BOOK02' AND a.NAME='AUTHOR03';
    INSERT INTO BOOK_AUTHOR (BOOK_ID,AUTHOR_ID) SELECT b.ID, a.ID FROM BOOK b, AUTHOR a WHERE b.TITLE='BOOK04' AND a.NAME='AUTHOR03';
    INSERT INTO BOOK_AUTHOR (BOOK_ID,AUTHOR_ID) SELECT b.ID, a.ID FROM BOOK b, AUTHOR a WHERE b.TITLE='BOOK04' AND a.NAME='AUTHOR05';
    INSERT INTO BOOK_AUTHOR (BOOK_ID,AUTHOR_ID) SELECT b.ID, a.ID FROM BOOK b, AUTHOR a WHERE b.TITLE='BOOK06' AND a.NAME='AUTHOR05';
    INSERT INTO BOOK_AUTHOR (BOOK_ID,AUTHOR_ID) SELECT b.ID, a.ID FROM BOOK b, AUTHOR a WHERE b.TITLE='BOOK06' AND a.NAME='AUTHOR07';
    INSERT INTO BOOK_AUTHOR (BOOK_ID,AUTHOR_ID) SELECT b.ID, a.ID FROM BOOK b, AUTHOR a WHERE b.TITLE='BOOK08' AND a.NAME='AUTHOR07';
    INSERT INTO BOOK_AUTHOR (BOOK_ID,AUTHOR_ID) SELECT b.ID, a.ID FROM BOOK b, AUTHOR a WHERE b.TITLE='BOOK08' AND a.NAME='AUTHOR09';
    INSERT INTO BOOK_AUTHOR (BOOK_ID,AUTHOR_ID) SELECT b.ID, a.ID FROM BOOK b, AUTHOR a WHERE b.TITLE='BOOK10' AND a.NAME='AUTHOR09';
    INSERT INTO BOOK_AUTHOR (BOOK_ID,AUTHOR_ID) SELECT b.ID, a.ID FROM BOOK b, AUTHOR a WHERE b.TITLE='BOOK10' AND a.NAME='AUTHOR11';
    INSERT INTO BOOK_AUTHOR (BOOK_ID,AUTHOR_ID) SELECT b.ID, a.ID FROM BOOK b, AUTHOR a WHERE b.TITLE='BOOK12' AND a.NAME='AUTHOR11';
    INSERT INTO BOOK_AUTHOR (BOOK_ID,AUTHOR_ID) SELECT b.ID, a.ID FROM BOOK b, AUTHOR a WHERE b.TITLE='BOOK12' AND a.NAME='AUTHOR13';
    INSERT INTO BOOK_AUTHOR (BOOK_ID,AUTHOR_ID) SELECT b.ID, a.ID FROM BOOK b, AUTHOR a WHERE b.TITLE='BOOK14' AND a.NAME='AUTHOR13';
    INSERT INTO BOOK_AUTHOR (BOOK_ID,AUTHOR_ID) SELECT b.ID, a.ID FROM BOOK b, AUTHOR a WHERE b.TITLE='BOOK14' AND a.NAME='AUTHOR15';
    INSERT INTO BOOK_AUTHOR (BOOK_ID,AUTHOR_ID) SELECT b.ID, a.ID FROM BOOK b, AUTHOR a WHERE b.TITLE='BOOK16' AND a.NAME='AUTHOR15';
    INSERT INTO BOOK_AUTHOR (BOOK_ID,AUTHOR_ID) SELECT b.ID, a.ID FROM BOOK b, AUTHOR a WHERE b.TITLE='BOOK16' AND a.NAME='AUTHOR17';
    INSERT INTO BOOK_AUTHOR (BOOK_ID,AUTHOR_ID) SELECT b.ID, a.ID FROM BOOK b, AUTHOR a WHERE b.TITLE='BOOK18' AND a.NAME='AUTHOR17';
    INSERT INTO BOOK_AUTHOR (BOOK_ID,AUTHOR_ID) SELECT b.ID, a.ID FROM BOOK b, AUTHOR a WHERE b.TITLE='BOOK18' AND a.NAME='AUTHOR19';
    INSERT INTO BOOK_AUTHOR (BOOK_ID,AUTHOR_ID) SELECT b.ID, a.ID FROM BOOK b, AUTHOR a WHERE b.TITLE='BOOK20' AND a.NAME='AUTHOR19';
    

    此时,如果您选择一本书,然后单击按钮提交页面,则作者列表将缩小为仅所选书的作者。 (反之亦然,如果您选择作者。)

    对于下一步,我需要刷新选择列表,而无需提交和刷新整个页面。

    让我们首先将级联设置添加到一个选择列表(P1_AUTHOR)中:

    enter image description here

    到现在为止还挺好。
    现在,当用户选择一本书时,作者选择列表会自动刷新。

    但是,在为其他选择列表配置级联设置时,也会遇到问题:

    enter image description here

    现在,当我们运行页面并尝试选择书籍或作者时,页面崩溃并出现Java脚本异常:

    enter image description here

    enter image description here

    错误是Maximum call stack size exceeded,它指示无限循环执行(带有递归)。

    这似乎可能是APEX代码中的错误/疏忽,因为使用正确/可靠的逻辑可以轻松解决技术问题。

    也就是说,我该如何解决?
    有没有其他方法可以配置级联选项来实现此目的?
    还是可以编写自定义动态操作和Javascript来手动提交单个项目,并手动刷新选择列表?

    最佳答案

    首先,我只想说问问题的方式! :)

    如您所见,“级联”部分是从父级流到子级的,而不是循环的(这可能导致堆栈溢出!抱歉,无法抗拒)。

    我会给您一个解决方案,但我会先承认它不是最佳选择,因为每次更改选择列表都将需要两个Ajax调用,而不仅仅是一个。我将向APEX团队提出这个问题,希望他们将来能解决。

    我将开始假设那些人已经运行了您的脚本并且有一个带有HTML区域的空白页,开始执行这些步骤。我的页面是53岁,因此人们需要相应地进行更改。

    第1部分:基础知识

  • 将页面项添加到该区域。将名称设置为 P53_BOOK ,将类型设置为选择,然后将值列表类型设置为 SQL查询。在 SQL查询字段中输入以下代码:
    select title d,
      id r
    from book
    where (
      :P53_AUTHOR is null
        or id in (
          select book_id
          from book_author
          where author_id = :P53_AUTHOR
        )
    )
    order by title
    
  • 将另一个项目添加到该区域。将名称设置为 P53_AUTHOR ,将类型设置为选择,然后将值列表类型设置为 SQL查询。在 SQL查询字段中输入以下代码:
    select name d,
      id r
    from author
    where (
      :P53_BOOK is null
        or id in (
          select author_id
          from book_author
          where book_id = :P53_BOOK
        )
    )
    order by name
    
  • 在页面设计器的“呈现” Pane 中,右键单击 P53_BOOK ,选择创建动态操作,然后将其名称设置为 P53_BOOK更改为。设置客户端条件并将键入 JavaScript表达式,然后在 JavaScript Expression 字段中输入以下代码:
    this.browserEvent.originalEvent !== undefined
    

    虽然看起来很奇怪,但是这将防止在刷新其他项目时触发动态 Action (防止发生其他循环逻辑问题;请参阅this for details)。
  • 在操作级别,将操作显示更改为执行PL / SQL代码。将 PL / SQL代码设置为null;项目,以将提交到 P53_BOOK 。该操作仅在更新操作之前用于更新P53_BOOK的 session 状态。
  • 添加一个在执行PL / SQL代码操作之后触发的新操作。将操作设置为刷新,将选择类型设置为项目,将项目设置为 P53_AUTHOR
  • 右键单击 P53_AUTHOR ,选择创建动态操作,然后将其名称设置为 P53_AUTHOR更改为。设置客户端条件并将键入 JavaScript表达式,然后在 JavaScript Expression 字段中输入以下代码:
    this.browserEvent.originalEvent !== undefined
    
  • 在操作级别,将操作更改为执行PL / SQL代码。将 PL / SQL代码设置为null;项目,以将提交到 P53_AUTHOR
  • 添加一个在执行PL / SQL代码操作之后触发的新操作。将操作设置为刷新,将选择类型设置为项目,将项目设置为 P53_BOOK

  • 如果您运行该程序,它应该可以正常工作(大部分情况下)。最大的问题是,如果对一项进行更改并刷新另一项,则即使刷新后该项目中存在刷新前的值,也会丢失另一项中的选择。

    如果可用,可以使用以下步骤自动重新选择该值。

    第2部分:恢复先前选择的值(可选)
  • 转到 P53_BOOK更改了动态操作。添加一个新的true Action ,该 Action 会在前两个 Action 之前触发。将操作设置为执行JavaScript代码,然后在代码字段中输入以下代码:
    $('#P53_BOOK').data('last-val', $v('P53_BOOK'));
    

    该代码使用jQuery的data方法存储预刷新项的值。您将在刷新后稍后使用它。
  • 转到 P53_AUTHOR更改了动态操作。添加一个新的true Action ,该 Action 会在前两个 Action 之前触发。将操作设置为执行JavaScript代码,然后在代码字段中输入以下代码:
    $('#P53_AUTHOR').data('last-val', $v('P53_AUTHOR'));
    
  • 右键单击 P53_BOOK ,然后选择创建动态操作。将名称设置为 P53_BOOK刷新了,并将事件设置为,然后刷新
  • 在操作级别,将操作设置为执行JavaScript代码,然后在代码字段中输入以下内容:
    $s('P53_BOOK', $('#P53_BOOK').data('last-val'), null, true);
    

    该代码使用data方法设置了P53_BOOK的值(这次是一个 setter/getter )。传递给$s的最后一个参数(true)以阻止change事件,否则将创建更多循环逻辑。
  • 右键单击 P53_AUTHOR ,然后选择创建动态操作。将名称设置为 P53_AUTHOR刷新了,并将事件设置为,然后刷新
  • 在操作级别,将操作设置为执行JavaScript代码,然后在代码字段中输入以下内容:
    $s('P53_AUTHOR', $('#P53_AUTHOR').data('last-val'), null, true);
    

  • 那应该做。但是还有一个烦人的事情……如果您在任何一个字段中选择一个空值,您可能希望它刷新两个字段(同时显示两个字段的所有选项),但那样行不通。如果需要的话,我建议您只添加一个单独的重置按钮。否则,最好用原始JavaScript代码编写所有这些代码。

    关于javascript - APEX:如何实现循环级联选择列表(多对多),我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/60676786/

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