Jasmine Testing 获取名称的完整描述/它的

Question

我想知道，是否可以获得测试的完整嵌套描述路径？

给定:

describe('Smoke Testing - Ensuring all pages are rendering correctly and free of JS errors', function () {
  describe('app', function () {
    describe('app.home', function () {
      it('should render this page correctly', function (done) {
        //name here should be: Smoke Testing - Ensuring all pages are rendering correctly and free of JS errors app app.home should render this page correctly
        done()
      })
    })

    describe('app.dashboard', function () {
      describe('app.dashboard.foobar', function () {
        it('should render this page correctly', function (done) {
        //name here should be: Smoke Testing - Ensuring all pages are rendering correctly and free of JS errors app app.dashboard app.dashboard.foobar should render this page correctly    
          done()
        })
      })
    })

  })

})

Answer 1

jasmine.Suite 和 jasmine.Spec 都有方法 getFullName()。如您所愿地工作:

describe("A spec within suite", function() {
  it("has a full name", function() {
    expect(this.getFullName()).toBe('A spec within suite has a full name.');    
  });
  
  it("also knows parent suite name", function() {
    expect(this.suite.getFullName()).toBe('A spec within suite');    
  });
});

<script src="http://searls.github.io/jasmine-all/jasmine-all-min.js"></script>

注意:这个答案现在有点过时了，示例中使用的是 Jasmine 1.3.1。