我从字典创建了以下 DataFrame:
clusters
OG1.5_1000 [6243|g1697.t1_CBS136243, 6243|g7411.t1_CBS136...
OG1.5_1001 [2003|g3159.t1_CBS132003, 2003|g4503.t1_CBS132...
OG1.5_1002 [4916|g1071.t1_CBS134916, 4916|g1248.t1_CBS134...
OG1.5_1003 [4916|g913.t1_CBS134916, 4920|g2467.t1_CBS1349...
OG1.5_1004 [2003|g2248.t1_CBS132003, 2003|g3254.t1_CBS132...
OG1.5_1005 [2003|g1615.t1_CBS132003, 2003|g1622.t1_CBS132...
当我尝试使用“,”作为分隔符进行拆分时，我得到的结果是多个“NaN”
df['clusters'].str.split(',')
OG1.5_1001 NaN
OG1.5_1002 NaN
OG1.5_1003 NaN
OG1.5_1004 NaN
OG1.5_1005 NaN
对我做错了什么有什么建议吗？或者我如何拆分“集群”列？
最佳答案
我认为需要 DataFrame 构造函数，因为在 clusters 中是 list:
#if one column DataFrame
df = pd.DataFrame(df['clusters'].values.tolist(), index=df.index)
#if multiple columns and need join new df to existing
df = df.join(pd.DataFrame(df.pop('clusters').values.tolist(), index=df.index))
关于python - Pandas str.split (' ' ) 返回 NaN，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/50529269/