假设我正在使用的 JSON 响应格式如下:
[
{
"make": "Tesla",
"model": "Model S",
"year": 2017,
"color": "red",
"owner": "Bob",
"max_speed": 200,
"wheel_size": 30,
"is_convertible": true,
"license": "ABC123",
"cost": 50000,
"down_payment": 2500,
"other_property_1": 1,
"other_property_2": 2,
"other_property_3": 3,
"other_property_4": 4,
"other_property_5": 5,
"other_property_6": 6,
"other_property_7": 7,
"other_property_8": 8,
"other_property_9": 9,
"other_property_10": 10,
"other_property_11": 11
}
]
这里的 JSON 是一个汽车对象数组(为简单起见,只有 1 个),我正在尝试使用 JSON Reads 转换器将其转换为模型。假设我有一个 Car case 类来表示每个对象,并且该类有一个嵌套的 FinancialInfo case 类来逻辑地拆分属性数量,从而避免 Scala 的 22 个参数限制。
import play.api.libs.functional.syntax._
import play.api.libs.json._
case class Car(
make: String,
model: String,
year: Int,
color: String,
owner: String,
maxSpeed: Int,
wheelSize: Int,
isConvertible: Boolean,
license: String,
financialInfo: FinancialInfo, // nested case class to avoid 22 param limit
otherProperty1: Int,
otherProperty2: Int,
otherProperty3: Int,
otherProperty4: Int,
otherProperty5: Int,
otherProperty6: Int,
otherProperty7: Int,
otherProperty8: Int,
otherProperty9: Int,
otherProperty10: Int,
otherProperty11: Int
)
object Car {
implicit val reads: Reads[Car] = (
(__ \ "make").read[String] and
(__ \ "model").read[String] and
(__ \ "year").read[Int] and
(__ \ "color").read[String] and
(__ \ "owner").read[String] and
(__ \ "max_speed").read[Int] and
(__ \ "wheel_size").read[Int] and
(__ \ "is_convertible").read[Boolean] and
(__ \ "license").read[String] and
(__ \ "financialInfo").read[FinancialInfo] and
(__ \ "other_property_1").read[Int] and
(__ \ "other_property_2").read[Int] and
(__ \ "other_property_3").read[Int] and
(__ \ "other_property_4").read[Int] and
(__ \ "other_property_5").read[Int] and
(__ \ "other_property_6").read[Int] and
(__ \ "other_property_7").read[Int] and
(__ \ "other_property_8").read[Int] and
(__ \ "other_property_9").read[Int] and
(__ \ "other_property_10").read[Int] and
(__ \ "other_property_11").read[Int]
)(Car.apply _)
}
case class FinancialInfo(
cost: BigDecimal,
downPayment: BigDecimal
)
object FinancialInfo {
implicit val reads: Reads[FinancialInfo] = (
(__ \ "cost").read[BigDecimal] and
(__ \ "down_payment").read[BigDecimal]
)(FinancialInfo.apply _)
}
但是,我猜测是因为 JSON 中没有名为
financialInfo
的属性。 ,它没有正确解析它。在我的实际应用程序中,当我使用 response.json.validate[List[Car]]
时出现此错误:JsError(List(((0)/financialInfo,List(JsonValidationError(List(error.path.missing),WrappedArray())))))
总而言之,在示例中,
cost
和 down_payment
不包含在嵌套对象中,即使对于 Car case 类我必须包含一个名为 financialInfo
的嵌套模型.解决此错误并确保 cost
的值的最佳方法是什么?和 down_payment
可以解析吗?任何帮助或见解将不胜感激!
最佳答案
Reads
可以相互组合和包含。
所以,有:
implicit val fiReads: Reads[FinancialInfo] = (
(JsPath \ "cost").read[BigDecimal] and
(JsPath \ "down_payment").read[BigDecimal]
)(FinancialInfo.apply _)
我们可以将它包含在父级
Reads
中:implicit val carReads: Reads[Car] = (
(JsPath \ "make").read[String] and
(JsPath \ "model").read[String] and
fiReads // <--- HERE!
)(Car.apply _)
现在,使用以下 JSON:
private val json =
"""
|[
| {
| "make": "Tesla",
| "model": "Model S",
| "cost": 50000,
| "down_payment": 2500
| },
| {
| "make": "Tesla",
| "model": "Model D",
| "cost": 30000,
| "down_payment": 1500
| }
|]
""".stripMargin
val parsedJsValue = Json.parse(json)
val parsed = Json.fromJson[List[Car]](parsedJsValue)
println(parsed)
它被正确解析:
JsSuccess(List(Car(Tesla,Model S,FinancialInfo(50000,2500)), Car(Tesla,Model D,FinancialInfo(30000,1500))),)
附言
Reads
原题中不需要包裹成不同的object
s。相关的隐式值在同一范围内会更好,更接近它们实际使用的位置。
关于json - 使用 Scala/Play 将 JSON 转换为带有嵌套对象的 case 类,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/50245602/