javascript - 克隆对象省略嵌套属性

Question

我想复制现有对象并省略一些属性。有没有一种简单的 es6+ 方法可以删除以下结构的嵌套栏键？

  someObj = { 
    someList: [
      { foo:'1', bar:'x', /*etc could be more values*/ },
      { foo:'2', bar:'x', /*etc could be more values*/ },
      { foo:'3', bar:'x', /*etc could be more values*/ },
    ],
    otherPropOne: '',
    anotherProp: [],
    //etc
  }

Answer 1

制作深拷贝并删除不需要的字段

let clone = JSON.parse(JSON.stringify(someObj)); 
clone.someList.forEach(x=> delete x.bar);

let someObj = { 
    someList: [
      { foo:'1', bar:'x',  },
      { foo:'2', bar:'x',  },
      { foo:'3', bar:'x',  },
    ],
    otherPropOne: '',
    anotherProp: [],
    //etc
  }
  
let clone = JSON.parse(JSON.stringify(someObj)); 
clone.someList.forEach(x=> delete x.bar);

console.log(clone);