我有一个名为 User
的 hibernate 对象,它与另一个名为 Post
的 hibernate 对象具有多对多关系。这种关系称为 likedPosts
(从 User
的角度来看)。
<set name="likedPosts" lazy="true" table="Likes" where="Deleted=0">
<cache usage="read-write"/>
<key column="UserID"/>
<many-to-many column="PostID" class="Post"/>
</set>
目前我有一个简单的 HQL 查询来返回喜欢的帖子列表,如下所示:
"select user.likedPosts from User user where user.id=:uid"
我想要的是让这个列表按 Post
对象(特别是帖子 ID)中的属性排序。我(天真的)尝试这样做是这样的:
"select user.likedPosts from User user where user.id=:uid
order by user.likedPosts.id desc"
虽然这不起作用 - 我收到一个异常,告诉我不允许这样做。我该怎么做呢?谢谢!
错误堆栈跟踪:
org.hibernate.QueryException: illegal attempt to dereference collection [user0_.ID.likedPosts] with element property reference [id] [select user.likedPosts from com.pashash.domain.User user where user.id=:uid order by user.likedPosts.id desc]
at org.hibernate.hql.ast.tree.DotNode$1.buildIllegalCollectionDereferenceException(DotNode.java:46)
at org.hibernate.hql.ast.tree.DotNode.checkLhsIsNotCollection(DotNode.java:513)
at org.hibernate.hql.ast.tree.DotNode.resolve(DotNode.java:221)
at org.hibernate.hql.ast.tree.FromReferenceNode.resolve(FromReferenceNode.java:94)
at org.hibernate.hql.ast.tree.FromReferenceNode.resolve(FromReferenceNode.java:90)
at org.hibernate.hql.ast.HqlSqlWalker.resolve(HqlSqlWalker.java:728)
...
最佳答案
你需要一个明确的连接来做到这一点:
select post from User user
inner join user.likedPosts post
where user.id = :userId
order by post.id desc
关于hibernate - HQL 按多对多集合属性排序,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/12780701/