我有一个名为日期的表,
Opendate | Closedate
------------+---------------
2015-07-09 | 2016-08-10
我期待这样的输出
opendate | closedate | diff
------------+---------------+----------------------
2015-07-09 | 2016-08-10 | 1year 1month 1day
2015-07-09 | 2016-03-01 | 8 months 20 days
2015-07-09 | 2015-07-11 | 2 days
但是当我运行这个查询时:
SELECT opendate,
closedate,
Datediff(year, opendate, closedate) AS years,
Datediff(month, opendate, closedate) AS months,
Datediff(day, opendate, closedate) AS days
FROM dates
它给我这样的输出,
opendate | closedate | years | months | days
------------+---------------+-------+--------+---------
2015-07-09 | 2016-08-10 | 1 | 13 | 397
如何计算1年1月1日
最佳答案
您可以使用 Stacked CTE 逐一查找下一年、下一个月和下一个日期。
解释
下面的查询首先找出 opendate 和 closedate 的 DATEDIFF
年,并检查结果日期是否大于 closedate。如果是,则实际年份差为 Y -1 的 DATEDIFF
。使用这个新日期并使用相同的逻辑获取月份的 DATEDIFF
,然后获取天数的差异。
查询
WITH D(Opendate,Closedate)AS
(
SELECT CAST('2015-07-09' AS DATE),CAST('2016-08-10' AS DATE)
UNION ALL
SELECT CAST('2015-07-09' AS DATE),CAST('2016-03-01' AS DATE)
UNION ALL
SELECT CAST('2015-07-09' AS DATE),CAST('2015-07-11' AS DATE)
),Y AS
(
SELECT Opendate,Closedate,
CASE
WHEN DATEADD(YEAR,DATEDIFF(YEAR,Opendate,Closedate),Opendate) > Closedate
THEN DATEDIFF(YEAR,Opendate,Closedate) - 1
ELSE DATEDIFF(YEAR,Opendate,Closedate)
END Years
FROM D
), YDate as
(
SELECT Opendate,Closedate,Years,DATEADD(YEAR,Years,Opendate) as Newopendate
FROM Y
),M AS
(
SELECT Opendate,Closedate,Years,Newopendate,
CASE WHEN DATEADD(MONTH,DATEDIFF(MONTH,Newopendate,Closedate),Newopendate) > Closedate
THEN DATEDIFF(MONTH,Newopendate,Closedate) - 1
ELSE DATEDIFF(MONTH,Newopendate,Closedate)
END Months
FROM YDate
)
SELECT Opendate,Closedate,Years,Months,DATEDIFF(Day,DATEADD(MONTH,Months,Newopendate),Closedate) as days
FROM M
结果
Opendate Closedate Years Months days
09-07-2015 00:00 10-08-2016 00:00 1 1 1
09-07-2015 00:00 01-03-2016 00:00 0 7 21
09-07-2015 00:00 11-07-2015 00:00 0 0 2
关于sql - 需要计算截止日期的年月日,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/38277673/