scala - 来自 Spark Streaming 的 Rest API 服务调用

Question

我有一个用例，在从 Kafka 读取消息以执行一些计算并将结果保存回 HDFS 和第三方应用程序后，我需要从 Spark 流中调用 RESTAPI。

我在这里有几个疑问:

我们如何直接从 Spark 流中调用 RESTAPI。

如何使用流式批处理时间管理 RESTAPI 超时。

Answer 1

此代码不会按原样编译。但这是给定用例的方法。

val conf = new SparkConf().setAppName("App name").setMaster("yarn")
val ssc = new StreamingContext(conf, Seconds(1))

val dstream = KafkaUtils.createStream(ssc, zkQuorum, group, topicMap)

dstream.foreachRDD { rdd =>

  //Write the rdd to HDFS directly
  rdd.saveAsTextFile("hdfs/location/to/save")

  //loop through each parttion in rdd
  rdd.foreachPartition { partitionOfRecords =>

    //1. Create HttpClient object here
    //2.a POST data to API

    //Use it if you want record level control in rdd or partion
    partitionOfRecords.foreach { record =>
      //2.b Post the the date to API
      record.toString
    }
  }
  //Use 2.a or 2.b to POST data as per your req
}

ssc.start()
ssc.awaitTermination()

大多数 HttpClients(用于 REST 调用)都支持请求超时。

使用 Apache HttpClient 超时的 Http POST 调用示例

val CONNECTION_TIMEOUT_MS = 20000; // Timeout in millis (20 sec).

val requestConfig = RequestConfig.custom()
  .setConnectionRequestTimeout(CONNECTION_TIMEOUT_MS)
  .setConnectTimeout(CONNECTION_TIMEOUT_MS)
  .setSocketTimeout(CONNECTION_TIMEOUT_MS)
  .build();

HttpClientBuilder.create().build();

val client: CloseableHttpClient = HttpClientBuilder.create().build();

val url = "https://selfsolve.apple.com/wcResults.do"
val post = new HttpPost(url);

//Set config to post
post.setConfig(requestConfig)

post.setEntity(EntityBuilder.create.setText("some text to post to API").build())

val response: HttpResponse = client.execute(post)