angular - 如何将参数传递给canActivate的构造函数？

Question

我有以下路线路径:

{
    path: 'teacher',
    component: DashboardTeacher, canActivate: [AccessGuardTeacher('Teacher')]
}

如您所见，我尝试在类AccessGuardTeacher中传递参数'Teacher':

export class AccessGuardTeacher implements CanActivate {

  constructor(private role: string) {
  }
}

怎么做对吗？

Answer 1

您的路线应配置为:

{ 
   path: 'teacher', 
   component: DashboardTeacherComponent, 
   canActivate: [AccessGuardTeacher], 
   data: { 
            role: 'teacher'
         } 
}

在您的CanActivate Guard中获取路线数据

export class AccessGuardTeacher implements CanActivate {

     constructor() {
     }

    canActivate(route: ActivatedRouteSnapshot): boolean {

        const role = route.data.role;
        return true; //based on your condition
    }
}