我正在使用带有 scala.I 的 Play 框架 2.1.1。我查询数据库表作为列表返回到 Controller ,然后将列表转换为字符串并从 javascript 代码返回到 ajax 调用。
如何将查询结果作为json返回并通过 Controller 返回ajax调用?
应用程序.scala
import play.api._
import play.api.mvc._
import play.api.data._
import views.html._
import models._
object Application extends Controller {
def index = Action {
Ok(views.html.index())
}
def getSummaryTable = Action{
var sum="Summary Table";
Ok(ajax_result.render((Timesheet.getAll).mkString("\n")))
}
def javascriptRoutes = Action { implicit request =>
import routes.javascript._
Ok(
Routes.javascriptRouter("jsRoutes")(
// Routes
controllers.routes.javascript.Application.getSummaryTable
)
).as("text/javascript")
}
}
TimeSheet.scala
// Use PostgresDriver to connect to a Postgres database
import scala.slick.driver.PostgresDriver.simple._
import scala.slick.lifted.{MappedTypeMapper,BaseTypeMapper,TypeMapperDelegate}
import scala.slick.driver.BasicProfile
import scala.slick.session.{PositionedParameters,PositionedResult}
// Use the implicit threadLocalSession
import Database.threadLocalSession
import java.sql.Date
import java.sql.Time
case class Timesheet(ID: Int, dateVal: String, entryTime: Time, exitTime: Time, someVal: String)
object Timesheet {
//Definition of Timesheet table
// object TS extends Table[(Int,String,Time,Time,String)]("timesheet"){
val TSTable = new Table[Timesheet]("timesheet"){
def ID = column[Int]("id")
def dateVal = column[String]("date")
def entryTime = column[Time]("entry_time")
def exitTime = column[Time]("exit_time")
def someVal = column[String]("someval")
def * = ID ~ dateVal ~ entryTime ~ exitTime ~ someVal <> (Timesheet.apply _, Timesheet.unapply _)
}
def getAll: Seq[Timesheet] = {
Database.forURL("jdbc:postgresql://localhost:5432/my_db", "postgres", "password",null, driver="org.postgresql.Driver") withSession{
val q = Query(TSTable)
val qFiltered = q.filter(_.ID === 41 )
val qDateFilter = qFiltered.filter(_.dateVal === "01/03/2013")
val qSorted = qDateFilter.sortBy(_.entryTime)
qSorted.list
}
}
}
最佳答案
另外,不要忘记为您的模型提供一个隐式(或不提供)Json 反序列化器,否则 Scala 编译器会对您大喊大叫 :-)。您可以执行以下操作:
def allTimesheet = Action {
val timesheetWrites = Json.writes[Timesheet] // here it's the deserializer
val listofTimeSheet = Timesheet.getAll
Ok( Json.toJson( listofTimeSheet )( timesheetWrites ) )
}
或者您可以使用隐式,例如:
def allTimesheet = Action {
implicit val timesheetWrites = Json.writes[Timesheet] // here it's the deserializer
val listofTimeSheet = Timesheet.getAll
Ok( Json.toJson( listofTimeSheet ) )
}
甚至在您的模型伴侣对象中声明您的反序列化器,例如:
伴生对象
object Timesheet {
implicit val timesheetWrites = Json.writes[Timesheet] // here it's the deserializer
....
}
并在 Controller 中
import models.Timesheet.timesheetWrites
def allTimesheet = Action {
val listofTimeSheet = Timesheet.getAll
Ok( Json.toJson( listofTimeSheet ) )
}
关于scala - 如何在Scala Play框架中以JSON形式返回模型查询结果,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/16977601/