Perl JSON 模块 |无法获得 JSON 响应

Question

我有一个用于填充 JQgrid 对象的脚本。以下代码在从 CLI 执行时构建似乎是有效的 JSON 查询

#!/usr/bin/perl 
use CGI;
use DBI;
use JSON;
use Test::JSON;
use POSIX qw(ceil);
use strict;
use warnings;

my $cgi = CGI->new;
my $page = $cgi->param('page');
my $limit = $cgi->param('limit');
my $sidx = $cgi->param('sidx');
my $sordx = $cgi->param('sordx');

if(!$sidx) {$sidx = 1};
my $start = $limit*$page - $limit;

my $dbh = DBI->connect('dbi:mysql:hostname=localhost;database=test',"test","test") or die $DBI::errstr;
my $count = $dbh->selectrow_array("SELECT COUNT(id) AS count FROM test;");
my $sql = "SELECT ID, Name FROM test ORDER BY ? ? LIMIT ?, ?;";
my $sth = $dbh->prepare($sql) or die $dbh->errstr;

$sth->execute($sidx,$sordx,$start,$limit) or die $sth->errstr;
my $total_pages;
if( $count >0 ) {
        $total_pages = ceil($count/$limit);
} else {
        $total_pages = 0;
}
if ($page > $total_pages){ $page=$total_pages};
$start = $limit*$page - $limit;
my $i=0;
my $response = {};
$response->{page} = $page;
$response->{total} = $total_pages;
$response->{records} = $count;
        while (my $row = $sth->fetchrow_arrayref) {
                my @arr = @{$row};
                $response->{rows}[$i]{id} = $row->[0];
                $response->{rows}[$i]{cell} = \@arr;
                $i++;
        }

Test::JSON::is_valid_json $response, '... json is well formed';

print $cgi->header(-type => "application/json", -charset => "utf-8");
print JSON::to_json($response,{ ascii => 1, pretty => 1 });

如果我将脚本置于 CGI Debug模式，它会返回以下内容(注意，手动编辑以屏蔽敏感数据):

{
   "page" : "1",
   "records" : "35",
   "rows" : [
      {
         "id" : "15675",
         "cell" : [
            "15675",
            "Test 1"
         ]
      },
      {
         "id" : "15676",
         "cell" : [
            "15676",
            "Test 2"
         ]
      }
   ],
   "total" : 4
}

编辑:我添加了 Test::JSON 包，它给了我以下错误:

input was not valid JSON: malformed JSON string, neither array, object, number, string or atom, at character offset 0 (before "(end of string)") at /usr/lib/perl5/site_perl/5.8.8/JSON/Any.pm line 571.

我不确定下一步该去哪里。我对代码所做的任何其他更改都不会在返回的字符串上放置适当的括号。

Answer 1

将此字符串传递给 JSON::decode ，我看到有人提示字符串中的文字换行符 "This is record 1"和 "This is record 2" .如果将它们转换为 \n 会怎样？ ?

foreach my $row ( @{$ref} ) {
    $response->{rows}[$i]{id} = @$row[0];
    $response->{rows}[$i]{cell} = $row;

    # escape newlines in database output
    s/\n/\\n/g for @{$response->{rows}[$i]{cell}};

    $i++;
}

(可能有一种更通用、更强大的方法来做到这一点)