rest - WCF RESTFul 服务中的异常处理

标签 rest web-services wcf exception wcf-rest

我正在使用 WCF Service 4.5 F/W 开发 REST Full API。请建议如何向客户发送异常或任何业务验证消息。我正在寻找一个非常通用的解决方案,请建议最好的方法。
我在下面尝试了一些方法,

  • 在向客户端发送响应之前设置 OutgoingWebResponseContext。
  • 定义的故障契约(Contract)仅工作正常 添加服务引用(代理类)在 REST FULL 环境中不起作用。
  • 在 catch 块中添加 WebFaultException 类。
  • WCF Rest Starter Kit - 我收到了一些关于此的文章和帖子,但他们的 CodePlex 官方网站建议不再提供此功能。 link .所以,我不想这样做。

  • 这些没有按预期工作..
    我的示例代码片段:
    界面:
        [OperationContract]
        [FaultContract(typeof(MyExceptionContainer))]
        [WebInvoke(Method = "GET", UriTemplate = "/Multiply/{num1}/{num2}", BodyStyle = WebMessageBodyStyle.Wrapped,RequestFormat = WebMessageFormat.Xml, ResponseFormat = WebMessageFormat.Xml)]
        string Multiply(string num1, string num2);
    

    执行:
             public string Multiply(string num1, string num2)
        {
            if (num1 == "0" || num2 == "0")
            {
                try
                {
                    MyExceptionContainer exceptionDetails = new MyExceptionContainer();
                    exceptionDetails.Messsage = "Business Rule violatuion";
                    exceptionDetails.Description = "The numbers should be non zero to perform this operation";
                    //OutgoingWebResponseContext outgoingWebResponseContext = WebOperationContext.Current.OutgoingResponse;
                    //outgoingWebResponseContext.StatusCode = System.Net.HttpStatusCode.ExpectationFailed;
                    //outgoingWebResponseContext.StatusDescription = exceptionDetails.Description.ToString();
                   // throw new WebFaultException<MyExceptionContainer>(exceptionDetails,System.Net.HttpStatusCode.Gone);
                    throw new FaultException<MyExceptionContainer>(exceptionDetails,new FaultReason("FaultReason is " + exceptionDetails.Messsage + " - " + exceptionDetails.Description));
                }
                catch (Exception ex)
                {
                    throw new FaultException(ex.Message);
                }
            }
    
            return Convert.ToString(Int32.Parse(num1) * Int32.Parse(num2));
        }
    

    网络配置:
      <system.serviceModel>
    <services>
      <service name="TestService.TestServiceImplementation" behaviorConfiguration="ServiceBehaviour">
        <endpoint binding="webHttpBinding" contract="TestService.ITestService" behaviorConfiguration="webHttp" >
        </endpoint>
      </service>
    </services>
    <behaviors>
      <serviceBehaviors>
        <behavior name="ServiceBehaviour">
          <!-- To avoid disclosing metadata information, set the value below to false and remove the metadata endpoint above before deployment -->
          <serviceMetadata httpGetEnabled="true"/>
          <!-- To receive exception details in faults for debugging purposes, set the value below to true.  Set to false before deployment to avoid disclosing exception information -->
          <serviceDebug includeExceptionDetailInFaults="true"/>
        </behavior>
      </serviceBehaviors>
      <endpointBehaviors>
        <behavior name="webHttp" >
          <webHttp helpEnabled="true" faultExceptionEnabled="true"/>
        </behavior>
      </endpointBehaviors>
    </behaviors>
    <serviceHostingEnvironment multipleSiteBindingsEnabled="true" />
    

    客户 :
    try
            {
                string serviceUrl = "http://localhost:51775/TestService.cs.svc/Multiply/0/0";
                //Web Client
                //WebClient webClient = new WebClient();
                //string responseString = webClient.DownloadString(serviceUrl);
                WebRequest req = WebRequest.Create(serviceUrl);
                req.Method = "GET";
                req.ContentType = @"application/xml; charset=utf-8";
                HttpWebResponse resp = req.GetResponse() as HttpWebResponse;
                if (resp.StatusCode == HttpStatusCode.OK)
                {
                    XmlDocument myXMLDocument = new XmlDocument();
                    XmlReader myXMLReader = new XmlTextReader(resp.GetResponseStream());
                    myXMLDocument.Load(myXMLReader);
                    Console.WriteLine(myXMLDocument.InnerText);
                }
                Console.ReadKey();
            }
            catch (Exception ex)
            { 
            Console.WriteLine(ex.Message);
            }
    

    这是我的第一个问题,感谢所有热情的开发人员..!

    最佳答案

    而不是 FaultException ,使用以下内容:

    服务器:

    catch (Exception ex)
                {
                    throw new System.ServiceModel.Web.WebFaultException<string>(ex.ToString(), System.Net.HttpStatusCode.BadRequest);
                }
    

    客户:
    catch (Exception ex)
                {
                    var protocolException = ex as ProtocolException;
                    var webException = protocolException.InnerException as WebException;
                    if (protocolException != null && webException != null)
                    {
                        var responseStream = webException.Response.GetResponseStream();
                        var error = new StreamReader(webException.Response.GetResponseStream()).ReadToEnd();
                        throw new Exception(error);
                    }
                    else
                        throw new Exception("There is an unexpected error with reading the stream.", ex);
    
                }
    

    关于rest - WCF RESTFul 服务中的异常处理,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/26070740/

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