我正在开发我正在调用网页的小应用程序。
我想在同一 View 中打开网页时覆盖 WebViewClient。
我的问题是如果发生任何问题(互联网连接中断或服务器断开连接)，那么我将显示自定义错误页面。
但是当 Internet 连接时，它显示相同的错误页面，而不是刷新的网页。
这是我的代码:
Web查看问题web；
字符串问题网址；
@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_main);
DetectConnection detectConnection = new DetectConnection(getApplicationContext());
ActionBar bar = getActionBar();
// for color
bar.setBackgroundDrawable(new ColorDrawable(Color.parseColor("#5b5959")));
questionweb = (WebView) findViewById(R.id.webView1);
if (!DetectConnection.checkInternetConnection(this)) {
Toast.makeText(getApplicationContext(), "No Internet!", Toast.LENGTH_SHORT).show();
AlertDialog alertDialog = new AlertDialog.Builder(
MainActivity.this).create();
// Setting Dialog Title
alertDialog.setTitle("Internet Connection");
// Setting Dialog Message
alertDialog.setMessage("Please Check Internet Connection");
// Setting OK Button
alertDialog.setButton("OK", new DialogInterface.OnClickListener() {
public void onClick(DialogInterface dialog, int which) {
// Write your code here to execute after dialog closed
Intent intent = new Intent(Settings.ACTION_WIFI_SETTINGS);
MainActivity.this.startActivity(intent);
}
});
// Showing Alert Message
alertDialog.show();
} else {
questionweb.getSettings().setJavaScriptEnabled(true);
// loads the WebView completely zoomed out
questionweb.getSettings().setLoadWithOverviewMode(true);
questionweb.getSettings().setUseWideViewPort(true);
// override the web client to open all links in the same webview
questionweb.setWebViewClient(new MyWebViewClient());
questionweb.setWebChromeClient(new MyWebChromeClient());
questionweb.addJavascriptInterface(new JavaScriptInterface(this),
"Android");
// load the home page URL
questionweb.loadUrl("http://10.2.1.119:8081/OnlineExamV2/login/loginpage");
}
// I am calling this to refresh the webpage
questionweb.loadUrl("javascript:window.location.reload( true )" );
}
private class MyWebViewClient extends WebViewClient {
@Override
public void onReceivedError(WebView view, int errorCode, String description, String failingUrl) {
super.onReceivedError(view, errorCode, description, failingUrl);
hideErrorPage(view);
}
private void hideErrorPage(WebView view) {
String customErrorPageHtml = "<html><body><table width=\"100%\" height=\"100%\" border=\"0\" cellpadding=\"0\" cellspacing=\"0\">"
+ "<tr>"
+ "<td><div align=\"center\"><font color=\"red\" size=\"22pt\">Sorry! Something went wrong</font></div></td>"
+ "</tr>" + "</table><html><body>";
view.loadData(customErrorPageHtml, "text/html", null);
}
@Override
public boolean shouldOverrideUrlLoading(WebView view, String url) {
questionweb.loadUrl(url);
//questionweb.loadUrl("http://10.2.1.119:8081/OnlineExamV2/login/loginpage");
questionweb.clearHistory();
return true;
}
}
private class MyWebChromeClient extends WebChromeClient {
// display alert message in Web View
@Override
public boolean onJsAlert(WebView view, String url, String message,
JsResult result) {
Log.d("Web", message);
new AlertDialog.Builder(view.getContext()).setMessage(message)
.setCancelable(true).show();
result.confirm();
return true;
}
}
如何在互联网恢复时刷新网页。
最佳答案
也许您可以试一试自己的 BroadcastReceiver 类。
像这样尝试(完全未经测试):
1.) GlobalState 类:
public GlobalState {
public static boolean isOnline = true;
public static String lastUrl = "";
}
2.) 在 onReceivedError 中保存上一个 url 和连接状态:
@Override
public void onReceivedError(WebView view, int errorCode, String description, String failingUrl) {
super.onReceivedError(view, errorCode, description, failingUrl);
GlobalState.isOnline = false;
GlobalState.lastUrl = failingUrl;
hideErrorPage(view);
}
3.)在你的 Activity 类中实现一个回调(我不知道名字，所以我称之为 MainActivity.java):
public class MainActivity extends Activity implements IConnectionCallback {
private ConnectionBroadReceiver cbr = null;
@Override
protected void onCreate(Bundle savedInstanceState) {
//some code...
cbr = new ConnectionBroadReceiver (this);
registerReceiver(cbr, new IntentFilter(ConnectivityManager.CONNECTIVITY_ACTION));
//some more code...
}
//this method will be triggered by ConnectionBroadCastReceiver
@Override
public void reload() {
//now reload your webview:
questionweb.loadUrl(GlobalState.lastUrl);
}
}
4.) 定义你的接口(interface)回调:
public interface IConnectionCallback {
public void reload();
}
5.) 最后但并非最不重要的 ConnectionBroadReceiver 类:
public class ConnectionBroadReceiver extends BroadcastReceiver {
private IConnectionCallback callback = null;
public ConnectionBroadReceiver (IConnectionCallback callback) {
this.callback = callback;
}
@Override
public void onReceive(Context context, Intent intent) {
ConnectivityManager cm = (ConnectivityManager)
context.getSystemService(Context.CONNECTIVITY_SERVICE);
NetworkInfo netInfo = cm.getActiveNetworkInfo();
// lets check the connection
if (netInfo != null && netInfo.isConnectedOrConnecting()) {
//when last state was the offline state (GlobalState.isOnline== false),
//lets trigger the callback
if (GlobalState.isOnline == false) {
callback.reload();
}
GlobalState.isOnline = true;
} else {
GlobalState.isOnline = false;
}
}
关于android - 如何在 onReceivedError 后恢复刷新的 Web View ，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/24955139/