SQL如何根据目标源上的数量将数量拆分为多行

标签 sql sql-server-2014 common-table-expression

我有两个表,我想在其中加入并显示详细信息的数量。
表与 ITM,DIA 连接,并且 ITM/DIA 组合的两个表中的总数量相等

我想在 table1 上拆分 table2 数量并将 table2 数据与 table1 数据一起填充。

我有以下数据供您引用,“table1”和“table2”。你可以在表“tableResult”中看到我的预期结果

CREATE TABLE table1
    (`ITM` varchar(5), `DIA` varchar(4), `LOC` varchar(4), `ID` varchar(3), `QTY` int)
;

INSERT INTO table1
    (`ITM`, `DIA`, `LOC`, `ID`, `QTY`)
VALUES
    ('Item1', 'DIA1', 'LOC1', 'ID1', 3),
    ('Item1', 'DIA1', 'LOC2', 'ID2', 4),
    ('Item1', 'DIA1', 'LOC2', 'ID2', 6),
    ('Item1', 'DIA2', 'LOC2', 'ID2', 6),
    ('Item1', 'DIA2', 'LOC3', 'ID3', 18),
    ('Item1', 'DIA2', 'LOC4', 'ID4', 90),
    ('Item1', 'DIA2', 'LOC4', 'ID5', 23),
    ('Item1', 'DIA3', 'LOC5', 'ID6', 50),
    ('Item1', 'DIA3', 'LOC6', 'ID7', 20),
    ('Item2', 'DIA1', 'LOC4', 'ID8', 44),
    ('Item2', 'DIA2', 'LOC5', 'ID8', 21),
    ('Item2', 'DIA3', 'LOC6', 'ID9', 20)
;


CREATE TABLE table2
    (`ITM` varchar(5), `DIA` varchar(4), `NTA` varchar(5), `QTY` int)
;

INSERT INTO table2
    (`ITM`, `DIA`, `NTA`, `QTY`)
VALUES
    ('Item1', 'DIA1', 'NTA1', 10),
    ('Item1', 'DIA1', 'NTA2', 3),
    ('Item1', 'DIA2', 'NTA3', 30),
    ('Item1', 'DIA2', 'NTA4', 7),
    ('Item1', 'DIA2', 'NTA5', 100),
    ('Item1', 'DIA3', 'NTA6', 70),
    ('Item2', 'DIA1', 'NTA7', 22),
    ('Item2', 'DIA1', 'NTA8', 20),
    ('Item2', 'DIA2', 'NTA9', 6),
    ('Item2', 'DIA2', 'NTA10', 15),
    ('Item2', 'DIA3', 'NTA11', 8),
    ('Item2', 'DIA3', 'NTA11', 12)
;


CREATE TABLE tableResult
    (`ITM` varchar(5), `DIA` varchar(4), `LOC` varchar(4), `ID` varchar(3), `QTY` int, `NTA` varchar(5), `NewQTY` int)
;

INSERT INTO tableResult
    (`ITM`, `DIA`, `LOC`, `ID`, `QTY`, `NTA`, `NewQTY`)
VALUES
    ('Item1', 'DIA1', 'LOC1', 'ID1', 3, 'NTA1', 3),
    ('Item1', 'DIA1', 'LOC2', 'ID2', 4, 'NTA1', 4),
    ('Item1', 'DIA1', 'LOC2', 'ID2', 6, 'NTA1', 3),
    ('Item1', 'DIA1', 'LOC2', 'ID2', 6, 'NTA2', 3),
    ('Item1', 'DIA2', 'LOC2', 'ID2', 6, 'NTA3', 6),
    ('Item1', 'DIA2', 'LOC3', 'ID3', 18, 'NTA3', 18),
    ('Item1', 'DIA2', 'LOC4', 'ID4', 90, 'NTA3', 6),
    ('Item1', 'DIA2', 'LOC4', 'ID4', 90, 'NTA4', 7),
    ('Item1', 'DIA2', 'LOC4', 'ID4', 90, 'NTA5', 77),
    ('Item1', 'DIA2', 'LOC4', 'ID5', 23, 'NTA5', 23),
    ('Item1', 'DIA3', 'LOC5', 'ID6', 50, 'NTA6', 50),
    ('Item1', 'DIA3', 'LOC6', 'ID7', 20, 'NTA6', 20),
    ('Item2', 'DIA1', 'LOC4', 'ID8', 44, 'NTA7', 22),
    ('Item2', 'DIA1', 'LOC4', 'ID8', 44, 'NTA8', 20),
    ('Item2', 'DIA2', 'LOC5', 'ID8', 21, 'NTA9', 6),
    ('Item2', 'DIA2', 'LOC5', 'ID8', 21, 'NTA10', 15),
    ('Item2', 'DIA3', 'LOC6', 'ID9', 20, 'NTA11', 8),
    ('Item2', 'DIA3', 'LOC6', 'ID9', 20, 'NTA11', 12)
;

下面是数据截图;
enter image description here

我可以使用 proc 并跟随游标来实现它,但我想使用 SQL 2014 有什么简单的方法,而且我知道 CTE 递归技巧会有所帮助。

你能分享一下你的解决方案吗?非常感谢您的宝贵想法。

最佳答案

您只需要将 table1 和 table2 的数量以单位分解,然后将它们并排耦合。
注意 FN_NUMBERS(n),它是一个函数,它只返回一列从 1 到 n 的数字,你的数据库中需要它,有很多方法可以做到,只需谷歌搜索“计数表”或 look here .
我使用以下内容:

CREATE FUNCTION FN_NUMBERS(
     @MAX INT
)
RETURNS @N TABLE (N INT NOT NULL PRIMARY KEY)  
BEGIN
     WITH
       Pass0 as (select '1' as C union all select '1'),       --2 rows
       Pass1 as (select '1' as C from Pass0 as A, Pass0 as B),--4 rows
       Pass2 as (select '1' as C from Pass1 as A, Pass1 as B),--16 rows
       Pass3 as (select '1' as C from Pass2 as A, Pass2 as B),--256 rows
       Pass4 as (select TOP (@MAX) '1' as C from Pass3 as A, Pass3 as B)    --65536 rows
       ,Tally as (select TOP (@MAX) '1' as C from Pass4 as A, Pass2 as B, Pass1 as C)  --4194304 rows
       --,Tally as (select TOP (@MAX) '1' as C from Pass4 as A, Pass3 as B)               --16777216 rows
       --,Tally as (select TOP (@MAX) '1' as C from Pass4 as A, Pass4 as B)               --4294836225 rows
     INSERT INTO @N
     SELECT TOP (@MAX) ROW_NUMBER() OVER(ORDER BY C) AS N
     FROM Tally
     RETURN
END

回到sql..
;with
t1 as (
    select *, ROW_NUMBER() over (partition by itm,dia order by loc,id) rn      
    from table1 t1
    join FN_NUMBERS(500) on n<=t1.qty
),
t2 as (
    select *, ROW_NUMBER() over (partition by itm,dia order by nta) rn      
    from table2 t2
    join FN_NUMBERS(500) on n<=t2.qty
),
t3 as (
    select t1.itm, t1.dia, t1.loc, t1.id, t1.qty, t2.nta, count(t1.n) NewQTY
    from  t1
    join  t2 on t1.itm=t2.itm and t1.dia = t2.dia and t1.rn=t2.rn
    group by t1.itm, t1.dia, t1.loc, t1.id, t1.qty, t2.nta
)
select * 
from t3
order by 1,2,3,4,5,6

关于SQL如何根据目标源上的数量将数量拆分为多行,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/40103444/

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