QCombobox 设置项目委托(delegate)不为当前项目绘制..
我正在尝试创建一个组合框,显示不同的线类型(实线、虚线、虚线等)。目前我正在为其内容设置项目委托(delegate)
以便绘制/绘制线型而不是显示名称。所有线型都在正确绘制,但只要我从
组合框,组合框的当前索引只显示行名而不是绘制它。我怎样才能让它在当前绘制选定的线型
组合框索引?
最佳答案
委托(delegate)在组合弹出窗口中绘制项目:
class LineStyleDelegate(QtGui.QItemDelegate):
def __init__(self, object, parent = None):
QtGui.QItemDelegate.__init__(self, parent)
def paint(self, painter, option, index):
data = index.model().data(index, QtCore.Qt.UserRole)
if data.isValid() and data.toPyObject() is not None:
data = data.toPyObject()
painter.save()
rect = option.rect
rect.adjust(+5, 0, -5, 0)
pen = QtGui.QPen()
pen.setColor(QtCore.Qt.black)
pen.setWidth(3)
pen.setStyle(data)
painter.setPen(pen)
middle = (rect.bottom() + rect.top()) / 2
painter.drawLine(rect.left(), middle, rect.right(), middle)
painter.restore()
else:
QtGui.QItemDelegate.paint(self, painter, option, index)
painter.drawLine(rect.left(), middle, rect.right(), middle)
painter.restore()
else:
QtGui.QItemDelegate.paint(self, painter, option, index)
paintEvent 以组合方式绘制当前项目。当然,您可以手动绘制它,但是有一种简单的方法可以绘制组合框控件本身(如果您想要当前的箭头按钮或 smth):
def paintEvent(self, e):
data = self.itemData(self.currentIndex(), QtCore.Qt.UserRole)
if data.isValid() and data.toPyObject() is not None:
data = data.toPyObject()
p = QtGui.QStylePainter(self)
p.setPen(self.palette().color(QtGui.QPalette.Text))
opt = QtGui.QStyleOptionComboBox()
self.initStyleOption(opt)
p.drawComplexControl(QtGui.QStyle.CC_ComboBox, opt)
painter = QtGui.QPainter(self)
painter.save()
rect = p.style().subElementRect(QtGui.QStyle.SE_ComboBoxFocusRect, opt, self)
rect.adjust(+5, 0, -5, 0)
pen = QtGui.QPen()
pen.setColor(QtCore.Qt.black)
pen.setWidth(3)
pen.setStyle(data)
painter.setPen(pen)
middle = (rect.bottom() + rect.top()) / 2
painter.drawLine(rect.left(), middle, rect.right(), middle)
painter.restore()
else:
QtGui.QComboBox.paintEvent(self, e)
关于qt - 如何为当前项目制作 QCombobox 绘画项目委托(delegate)? (Qt 4),我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/516032/