我有两个 LatLong 点:矩形的左上点和右下点，我想使用 Google Maps API 检索此矩形的卫星图像。
我知道，由于缩放级别是一个整数，我可能无法获得这个精确的矩形，但是如果我获得更大的像素图就没有问题，只要我能够在 latlong 坐标中计算像素图的边界框。
由于像素图大小是固定的(比如 640x640)并且我有它的中心，如何找到合适的缩放级别并计算像素图的边界框？
最佳答案
在提供CalculateBoundsZoomLevel 函数的旧Google Maps API 博客中找到了一个python 引用链接。
源文件是here .
def CalculateBoundsZoomLevel(self, bounds, view_size):
"""Given lat/lng bounds, returns map zoom level.
This method is used to take in a bounding box (southwest and northeast
bounds of the map view we want) and a map size and it will return us a zoom
level for our map. We use this because if we take the bottom left and
upper right on the map we want to show, and calculate what pixels they
would be on the map for a given zoom level, then we can see how many pixels
it will take to display the map at this zoom level. If our map size is
within this many pixels, then we have the right zoom level.
Args:
bounds: A list of length 2, each holding a list of length 2. It holds
the southwest and northeast lat/lng bounds of a map. It should look
like this: [[southwestLat, southwestLat], [northeastLat, northeastLng]]
view_size: A list containing the width/height in pixels of the map.
Returns:
An int zoom level.
"""
zmax = 18
zmin = 0
bottom_left = bounds[0]
top_right = bounds[1]
backwards_range = range(zmin, zmax)
backwards_range.reverse()
for z in backwards_range:
bottom_left_pixel = self.FromLatLngToPixel(bottom_left, z)
top_right_pixel = self.FromLatLngToPixel(top_right, z)
if bottom_left_pixel.x > top_right_pixel.x :
bottom_left_pixel.x -= self.CalcWrapWidth(z)
if abs(top_right_pixel.x - bottom_left_pixel.x) <= view_size[0] \
and abs(top_right_pixel.y - bottom_left_pixel.y) <= view_size[1] :
return z
return 0
关于google-maps - 在 Google Static Maps API 中获取矩形的图像，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/4267121/