我有一个具有以下三个维度的多维数据集:日期、时间和类次。我有一个名为 [Pieces Succeeded] 的度量,我想要一个类次按小时计算的 [Pieces Succeeded] 总计。 Shift 可以跨越一天以上,因此在以下查询中,我对日期和时间维度进行了交叉连接。
with
member [Measures].[Pieces Succeeded Running Total] as
sum([Time].[Hierarchy].[Hour].FirstMember:[Time].[Hour].CurrentMember, [Measures].[Pieces Succeeded])
select
{ [Measures].[Pieces Succeeded], [Measures].[Pieces Succeeded Running Total] } on columns,
nonempty(crossjoin([Date].[Month Hierarchy].[Day].Members, [Time].[Hierarchy].[Hour].Members)) on rows
from
[OEE]
where
[Shift].[Month Hierarchy].[Shift].&[501]
这给出了以下结果:
Date Hour Pieces Succeeded Pieces Succeeded Running Total
03 Apr 2011 22 6393 6393
03 Apr 2011 23 6424 12817
04 Apr 2011 00 3816 3816
04 Apr 2011 01 5510 9326
04 Apr 2011 02 2090 11416
04 Apr 2011 03 7489 18905
04 Apr 2011 04 7307 26212
04 Apr 2011 05 5706 31918
我将如何让总和在交叉连接集上工作,以便运行总计在几天内工作?
谢谢
最佳答案
我花了一整天的时间,终于弄明白了。我认为它可能对其他人有值(value),所以这是解决方案:
with
set DateHours as
nonempty(crossjoin([Date].[Month Hierarchy].[Day].Members, [Time].[Hierarchy].[Hour].Members), [Measures].[Pieces Succeeded])
member [Measures].[Rank] as
rank(([Date].[Month Hierarchy].CurrentMember, [Time].[Hierarchy].CurrentMember ), DateHours)
member [Measures].[Running Pieces Succeeded] as
iif([Measures].[Rank] = 1, [Measures].[Pieces Succeeded], sum(head(DateHours, [Measures].[rank]), [Measures].[Pieces Succeeded]))
select
{ [Measures].[Pieces Succeeded], [Measures].[Running Pieces Succeeded] } on columns,
non empty { DateHours } on rows
from
[OEE]
where
[Shift].[Month Hierarchy].[Shift].&[501]
关于ssas - 跨交叉连接维度运行总计的 MDX 查询,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/10086791/