我已经为此工作了 2 天,但我无法弄清楚。我希望有比我更聪明的人来试一试。
假设我有以下表格:
Rating:
Id | Name
1 | A
2 | B
3 | C
4 | D
5 | E
Inspection:
Id | Date (mm/dd/yyyy)
1 | 01/04/2012
2 | 04/04/2012
3 | 28/03/2012
4 | 04/04/2012
Observation:
Id | InspectionId | RatingId
1 | 2 | 3
2 | 1 | 2
3 | 4 | 3
4 | 2 | 1
5 | 3 | 3
6 | 1 | 2
我希望查询返回:
RatingName | Date(mm/dd/yyyy) | ObservationCount
A | 01/04/2012 | 0
B | 01/04/2012 | 1
C | 01/04/2012 | 1
D | 01/04/2012 | 0
E | 01/04/2012 | 0
A | 04/04/2012 | 1
B | 04/04/2012 | 0
C | 04/04/2012 | 2
D | 04/04/2012 | 0
E | 04/04/2012 | 0
A | 28/03/2012 | 0
B | 28/03/2012 | 0
C | 28/03/2012 | 1
D | 28/03/2012 | 0
E | 28/03/2012 | 0
所以我需要每个日期的每个评级的观察次数。是的,我需要有返回 0 Observations 的记录,因为我在堆积图中使用这些数据,没有它们会引发错误。我已经设法获得了上表,但没有使用以下 Linq To Sql 查询返回 0 Observations 的记录,但从这一点上我被卡住了。
MyDataContext DB = new MyDataContext();
var data =
(from r in DB.Ratings
join o in DB.Observations on r.Id equals o.RatingId into ro
from observation in ro.DefaultIfEmpty()
join i in DB.Inspections on observation.InspectionId equals i.Id into roi
from q in roi.DefaultIfEmpty()
group q by new { Name = r.Name, Date = q.Date } into grouped
select
new
{
RatingName = grouped.Key.Name,
Date = grouped.Key.Date,
ObservationCount = grouped.Count(x => x != null)
}).OrderBy(x => x.Date);
我希望能在 Linq To Sql 或简单的旧 SQL 中得到答案,谢谢!
最佳答案
你应该试试 CROSS JOIN
在两个引用表上,然后 OUTER JOIN
回到你的“数据”表——然后检查是否Observation
为空...然后分组和求和!
SELECT
[Name],
[Date],
SUM([Exists])
FROM
(
SELECT
name,
[Date],
CASE WHEN o.Id IS NULL THEN 0
ELSE 1
END as [Exists]
FROM
Rating r CROSS JOIN
Inspection i
LEFT OUTER JOIN Observation o
ON o.RatingId = r.Id AND o.InspectionId = i.Id
) as [source]
GROUP BY [Name], [Date]
ORDER BY
[Date],
name
转换为 LINQ 将是一个类似的两步过程 - 在分组和求和之前获取内部结果集(检查观察是否为 NULL)。
关于sql - Linq To Sql 或 SQL 中的困难查询,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/11534948/