Django 将自定义表单参数传递给 ModelFormset

标签 django filtering django-forms

我的问题类似于 Django Passing Custom Form Parameters to Formset

我有这些课

class Game(models.Model):
    home_team = models.ForeignKey(Team, related_name='home_team')
    away_team = models.ForeignKey(Team, related_name='away_team')
    round = models.ForeignKey(Round)

TEAM_CHOICES = ((1, '1'), (2, 'X'), (3, '2'),)

class Odds(models.Model):
    game = models.ForeignKey(Game, unique=False)
    team = models.IntegerField(choices = TEAM_CHOICES)
    odds = models.FloatField()
    class Meta:
        verbose_name_plural = "Odds"
        unique_together = (
            ("game", "team"),
        )

class Vote(models.Model):
    user = models.ForeignKey(User, unique=False)
    game = models.ForeignKey(Game)
    score = models.ForeignKey(Odds)
    class Meta:
        unique_together = (
            ("game", "user"),)

我已经定义了我自己的modelformset_factory:
def mymodelformset_factory(ins):
    class VoteForm(forms.ModelForm):
        score = forms.ModelChoiceField(queryset=Odds.objects.filter(game=ins), widget=forms.RadioSelect(), empty_label=None)
        def __init__(self, *args, **kwargs):
            super(VoteForm, self).__init__(*args, **kwargs)
        class Meta:
            model = Vote
            exclude = ['user']
    return VoteForm 

我像这样使用它:
        VoteFormSet = modelformset_factory(Vote, form=mymodelformset_factory(v), extra=0)
        formset = VoteFormSet(request.POST, queryset=Vote.objects.filter(game__round=round, user=user))

这将显示表单:

指定回合中游戏的下拉框,应该为赔率显示 3 个单选按钮,但我不知道将什么作为参数传递给 mymodelformset_factory .. 如果 v = Game.objects.get(pk =1)它显然只为所有游戏显示 pk=1 的游戏,我需要的是 v = Game.objects.get(pk="game who is connected to the chances about") 如果你发现我的漂移..

最佳答案

我认为您想对自定义工厂功能进行一些更改。它应该返回表单集类,而不是表单。这个怎么样:

def make_vote_formset(game_obj, extra=0):
    class _VoteForm(forms.ModelForm):
        score = forms.ModelChoiceField(
            queryset=Odds.objects.filter(game=game_obj), 
            widget=forms.RadioSelect(), 
            empty_label=None)

        class Meta:
            model = Vote
            exclude = ['user',]
    return modelformset_factory(Vote, form=_VoteForm, extra=extra)

然后在您的 View 代码中:
current_game = Game.objects.filter(id=current_game_id)
VoteFormSet = make_vote_formset(current_game)
formset = VoteFormSet(
             request.POST, 
             queryset=Vote.objects.filter(game__round=round, user=user))

关于Django 将自定义表单参数传递给 ModelFormset,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/1215040/

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