java - 带有 header 参数的Get方法无法正常工作android

Question

我有以下 JSON:

{
  "category": [{
    "id": "90",
    "user_id": "1",
    "category_id": "27",
    "name": "આણંદ કોમર્સિયલ લેયર",
    "order": "0",
    "created_at": "2014-05-03 17:09:54",
    "updated_at": "2014-05-03 17:09:54",
    "deleted": "0",
    "subtopics": [{
      "id": "203",
      "user_id": "1",
      "category_id": "27",
      "subcategory_id": "90",
      "name": "આણંદ કોમર્સિયલ લેયર (સંકર જાત)",
      "order": "0",
      "details": "<p style=\"text-align:justify\"><img alt=\"\" src=\"/packages/wysiwyg/ckeditor/plugins/kcfinder/upload/images/1.png\" style=\"height:271px; width:237px\" /></p>\r\n\r\n<ul>\r\n\t<li style=\"text-align:justify\">પ્રથમ ઈંડું મુક્વાની સરેરાશ ઉંમર:૧૪૨ દિવસ</li>\r\n\t<li style=\"text-align:justify\">સરેરાશ વાર્ષિક ઈંડા ઉત્પાદન : ૩૦૦ ઈંડા</li>\r\n\t<li style=\"text-align:justify\">૪૦ અઠવાડીયાની ઉંમરે ઈંડાનું સરેરાશ વજન : ૫૨ ગ્રામ</li>\r\n\t<li style=\"text-align:justify\">૭૨ અઠવાડીયાની ઉંમરે ઈંડાનું સરેરાશ વજન : ૫૪ ગ્રામ</li>\r\n\t<li style=\"text-align:justify\">સારી જીવાદોરી</li>\r\n</ul>\r\n",
      "mobile_detail": "<p style=\"text-align:justify\"><img alt=\"\" src=\"/packages/wysiwyg/ckeditor/plugins/kcfinder/upload/images/1.png\" style=\"height:271px; width:237px\" /></p>\r\n\r\n<ul>\r\n\t<li style=\"text-align:justify\">પ્રથમ ઈંડું મુક્વાની સરેરાશ ઉંમર:૧૪૨ દિવસ</li>\r\n\t<li style=\"text-align:justify\">સરેરાશ વાર્ષિક ઈંડા ઉત્પાદન : ૩૦૦ ઈંડા</li>\r\n\t<li style=\"text-align:justify\">૪૦ અઠવાડીયાની ઉંમરે ઈંડાનું સરેરાશ વજન : ૫૨ ગ્રામ</li>\r\n\t<li style=\"text-align:justify\">૭૨ અઠવાડીયાની ઉંમરે ઈંડાનું સરેરાશ વજન : ૫૪ ગ્રામ</li>\r\n\t<li style=\"text-align:justify\">સારી જીવાદોરી</li>\r\n</ul>\r\n",
      "created_at": "2014-05-03 17:11:43",
      "updated_at": "2014-05-11 13:41:31",
      "deleted": "0",
      "images": [],
      "videos": []
    }]
  }]
}

我有以下代码:

public JSONObject getJSONFromUrl(String url) {

    // Making HTTP request
    InputStream is=null;
    try {
        // defaultHttpClient
        DefaultHttpClient httpClient = new DefaultHttpClient();
        //HttpPost httpPost = new HttpPost(url);
        HttpGet httpPost = new HttpGet(url);
        httpPost.setHeader("Content-Type", "application/json");
        httpPost.setHeader("X-Requested-With", "XMLHttpRequest");
        httpPost.setHeader("Mobile-Tokon", "7c^4N:9Y*Tq;P^f");
        HttpResponse httpResponse = httpClient.execute(httpPost);
        HttpEntity httpEntity = httpResponse.getEntity();
        is = httpEntity.getContent();

    } catch (UnsupportedEncodingException e) {
        e.printStackTrace();
    } catch (ClientProtocolException e) {
        e.printStackTrace();
    } catch (IOException e) {
        e.printStackTrace();
    }

    String json="";
    try {
        BufferedReader reader = new BufferedReader(new InputStreamReader(is, "UTF-8"), 8000);
        StringBuilder sb = new StringBuilder();
        String line = null;
        while ((line = reader.readLine()) != null) {
            sb.append(line + "\n");
        }
        is.close();
        json = sb.toString();
    } catch (Exception e) {
        Log.e("Buffer Error", "Error converting result " + e.toString());
    }

    // try parse the string to a JSON object
    JSONObject jObj=null;
    try {
        jObj = new JSONObject(json);
        Log.d("JSON",jObj.toString());
    } catch (JSONException e) {
        Log.e("JSON Parser", "Error parsing data " + e.toString());
    }

    // return JSON String
    return jObj;

}

在我的 Java 类中，我这样调用上面的函数:

getJSONFromUrl("http://ikishan.192.168.1.87.xip.io/api/newapps/27?email=api.ikisan@aau.in&password=%~?7ON9Xjp;BcYu");

我得到一个错误:

java.lang.IllegalArgumentException: Invalid % sequence: %~? in query at index 83: http://ikishan.192.168.1.87.xip.io/api/newapps/27?email=api.ikisan@aau.in&password=%~?7ON9Xjp;BcYu

在这一行:

HttpGet httpPost = new HttpGet(url);

知道如何解决这个问题吗？

编辑

Answer 1

那是因为您提到的 URL 不是 this 中指定的有效 URL所以回答。

a complete URL is always in its encoded form: you take the strings for the individual components (scheme, authority, path, etc.), encode each according to its own rules, and then combine them into the complete URL string. Trying to build a complete unencoded URL string and then encode it separately leads to subtle bugs, like spaces in the path being incorrectly changed to plus signs (which an RFC-compliant server will interpret as real plus signs, not encoded spaces).

IllegalArgumentException异常中提到的那些无效字符不应该直接用GET请求发送，需要转换成这种格式

Character   From Windows-1252   From UTF-8
  %               %25               %25
  ~               %7E               %7E
  ?               %3F               %3F

参见 this完整列表的网址

---

在 Java 中，构建 URL 的正确方法是使用 URI 类。

import java.net.URLEncoder;

public class HelloWorld {
    static String uri = "http://ikishan.192.168.1.87.xip.io/api/newapps/27";
    static String params = "?email=api.ikisan@aau.in&password=%~?7ON9Xjp;BcYu";

     public static void main(String []args){
        try {
            String encodedParams = URLEncoder.encode( params, "ASCII" ).toString();
            System.out.println(uri + encodedParams);
        }
        catch(java.io.UnsupportedEncodingException uee) {
            //do something
        }
     }
}

输出

http://ikishan.192.168.1.87.xip.io/api/newapps/27%3Femail%3Dapi.ikisan%40aau.in%26password%3D%25%7E%3F7ON9Xjp%3BBcYu