我有这个 JSON 文件:
{
"CARD_MODEL_TITLE": "OWNER'S MANUAL",
"CARD_MODEL_SUBTITLE": "Configure your download",
"CARD_MODEL_SELECT": "Select Model",
"CARD_LANG_TITLE": "Select Language",
"CARD_LANG_DEVICE_LANG": "Your device",
"CARD_YEAR_TITLE": "Select Model Year",
"CARD_YEAR_LATEST": "(Latest)",
"STEPS_MODEL": "Model",
"STEPS_LANGUAGE": "Language",
"STEPS_YEAR": "Model Year",
"BUTTON_BACK": "Back",
"BUTTON_NEXT": "Next",
"BUTTON_CLOSE": "Close"
}
我用来在 Powershell 中将其转换为 JSON 对象的语法是这样的:
$json = (Get-Content "jsonfile.json") -join "`n" | ConvertFrom-Json
问题是我想编辑每对名称/值的值,但名称字段在其他文件中可能会有所不同,并且由于我想要每个文件的单个脚本,因此必须是通用的。
如何在事先不知道名称字段的情况下获取名称/值对的名称字段?或者换句话说,我想要一种:
foreach ($i in $json)
谢谢
最佳答案
您可以在转换后使用 $json.psobject.properties.name :
@'
{
"CARD_MODEL_TITLE": "OWNER'S MANUAL",
"CARD_MODEL_SUBTITLE": "Configure your download",
"CARD_MODEL_SELECT": "Select Model",
"CARD_LANG_TITLE": "Select Language",
"CARD_LANG_DEVICE_LANG": "Your device",
"CARD_YEAR_TITLE": "Select Model Year",
"CARD_YEAR_LATEST": "(Latest)",
"STEPS_MODEL": "Model",
"STEPS_LANGUAGE": "Language",
"STEPS_YEAR": "Model Year",
"BUTTON_BACK": "Back",
"BUTTON_NEXT": "Next",
"BUTTON_CLOSE": "Close"
}
'@ | set-content jsonfile.json
$json = (Get-Content "jsonfile.json" -Raw) | ConvertFrom-Json
$json.psobject.properties.name
CARD_MODEL_TITLE
CARD_MODEL_SUBTITLE
CARD_MODEL_SELECT
CARD_LANG_TITLE
CARD_LANG_DEVICE_LANG
CARD_YEAR_TITLE
CARD_YEAR_LATEST
STEPS_MODEL
STEPS_LANGUAGE
STEPS_YEAR
BUTTON_BACK
BUTTON_NEXT
BUTTON_CLOSE
您还可以消除
-join
通过使用 -Raw
与 Get-Content
切换
关于json - 不知道如何在Powershell中获取JSON对象的名称字段?,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/23062087/