例如我想替换字符 "A"
用于“Apple”和字符 "B"
为“版纳”
junk <- data.frame(x = rep(LETTERS[1:4], 3),
y = letters[1:12],
stringsAsFactors = FALSE)
这提供:
x y
1 A a
2 B b
3 C c
4 D d
5 A e
6 B f
7 C g
8 D h
9 A i
10 B j
11 C k
12 D l
我试着用
library(dplyr)
library(stringr)
mutate_if(junk,
is.character,
str_replace_all, pattern = "A", replacement = "Apple")
但是,当我尝试对“B”执行相同操作时,它删除了“A”的先前替换。我想保留这两个结果。
mutate_if(junk,
is.character,
str_replace_all, pattern = "A", replacement = "Apple")
我想同时保留结果“Apple”和“Bannana”
最佳答案
您可能正在寻找:
junk %>%
mutate_if(is.character, str_replace_all, c("A" = "Apple", "B" = "Banana"))
x y
1 Apple a
2 Banana b
3 C c
4 D d
5 Apple e
6 Banana f
7 C g
8 D h
9 Apple i
10 Banana j
11 C k
12 D l
关于替换数据上的字符,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/58511774/