如果 Moose 的构造函数调用中有额外的参数不是属性,有没有办法死?例如,这个:
package Shoe;
use Moose;
has 'size' => (is => 'ro', isa => 'Num');
has 'color' => (is => 'ro', isa => 'Str', default => 'brown');
1;
会死在
my $sneaker = Shoe->new(size => 11, colour => 'white');
因为
colour
不是 Shoe
的属性.我可以发誓我已经看到了一个模块或其他东西可以做到这一点,但我找不到它。
最佳答案
对我来说作品MooseX::StrictConstructor :
package Shoe;
use Moose;
use MooseX::StrictConstructor; # <-- that's all what need
has 'size' => (is => 'ro', isa => 'Num');
has 'color' => (is => 'ro', isa => 'Str');
1;
package main;
my $sneaker = Shoe->new(size => 11, colour => 'white'); #blows up
关于perl - 禁止 Moose 类中的非属性参数,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/25860844/