我正在尝试解决 Swift 中的编码挑战。任务是构建一个接受一系列方向的函数,例如:["NORTH", "WEST", "EAST", "NORTH", "EAST", "SOUTH"]
.应删除阵列中彼此相邻的任何相反方向。使用上面的示例,应该删除第二个和第三个索引(“WEST”和“EAST”)。但是,最后一个索引“SOUTH”应该保留,因为它不直接紧邻数组中的“NORTH”值。
我正在尝试实现一个堆栈以比较这些值,但无法使其正常工作。这是我第一次实现堆栈,而且我仍然在习惯 Swift 语法。
我的代码是这样设置的:
struct StringStack {
var array: [String] = []
func peek() -> String {
guard let topElement = array.first else { fatalError("The Stack is empty.")}
return topElement
}
mutating func pop() -> String {
return array.removeFirst()
}
mutating func push(_ element: String) {
array.insert(element, at: 0)
}
}
func directionsReduce(_ directions: [String]) -> [String] {
var reducedDirs = StringStack()
reducedDirs.push(directions[1])
for direction in directions {
if((direction == "NORTH" && reducedDirs.peek() == "SOUTH")
|| (direction == "SOUTH" && reducedDirs.peek() == "NORTH")
|| (direction == "EAST" && reducedDirs.peek() == "WEST")
|| (direction == "WEST" && reducedDirs.peek() == "EAST")
) {
reducedDirs.pop()
} else {
reducedDirs.push(direction)
}
}
return reducedDirs.array
}
let testDirections1 = ["WEST", "WEST", "NORTH", "SOUTH", "EAST", "WEST"]
print(directionsReduce(testDirections1))
我所拥有的返回一个数组
["WEST", "WEST", "WEST"]
,但是,这应该返回 ["WEST", "WEST"]
.我不确定如何初始化堆栈以解决此问题。我很感激任何可以看一看的新鲜眼睛。我也很好奇这是否是实现堆栈的最佳实践,或者是否有更好的方法来应对这一挑战。感谢任何帮助或建议。
最佳答案
对于列表中的其余元素(方向 [1:]),将元素添加到堆栈 如果堆栈为空 或 如果peek的结果和元素不是相反的方向 .否则,弹出堆栈顶部的元素并继续下一个。
大小/长度方法对您的堆栈实现很有用。它会在 peek()
之前提供支票防止抛出 fatalError
func directionsReduce(_ directions: [String]) -> [String] {
var reducedDirs = StringStack()
reducedDirs.push(directions[0])
for direction in directions[1...] {
if ((reducedDirs.length() == 0)
|| (!areOppositeDirections(direction, reducedDirs.peek()))
{
reducedDirs.push(direction)
} else {
reducedDirs.pop()
}
}
return reducedDirs.array
}
let testDirections1 = ["WEST", "WEST", "NORTH", "SOUTH", "EAST", "WEST"]
print(directionsReduce(testDirections1))
关于arrays - 如何在 Swift 中的方向数组缩减挑战中正确实现堆栈,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/60066397/